Answer:
see below
Step-by-step explanation:
1) see attached image
2) <u> bearings from A to B</u>
Note: bearing is always clockwise from A and from North.
(i)
bearing 180° + 67°
247° from N
(ii)
bearing 148 + 180
328° from N
(iii)
bearing 180 - 21
159° from N
(iv)
39° from N
(v)
bearing 90 - 40
50° from N
3) <u>back bearing from each diagram on no. 2</u>
<u />
Note: subtract 200 if bearing is more than 180
add 180 if the bearing is less than 180
(i) 247 - 200 = 47°
(ii) 328 - 200 = 128°
(iii) 159 + 180 = 339°
(iv) 39 + 180 = 219°
(v) 50 + 180 = 230°
193.93524
That’s what I got
<span>If Hunter raises beetles in a square of compost with a size of 6 ft by 6 ft and having 500 beetles, and then you are to find the number of beetles with a side length that is four times longer, then you can solve this by ratio and proportion.
A = s</span>²
A = 6²
A = 36 ft²
if s = 4*the original length, then the new area is
A = 24²
A = 576 ft²
500 beetles/36 ft² = x number of beetles/576 ft²
x = 8,000 beetles
Point yes but not them for sure but i just said they don’t want yip be in a bad place