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3 years ago

13

Convert this decimal into its fractional

1 answer:

lana66690 [7]3 years ago

8 0

0.1 = 10/100

= 1/10

The final answer should be 1/10

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Write an equation of the line passing through (-5,5) and having slope -6. Guve the answer in slope-intercept form.

Fynjy0 [20]

Passes through (-5, 5) & has a slope of -6.

We want the answer in slope-intercept form.

** Remember! Slope-intercept form : y=mx+b where m=slope, b=y-intercept.

Simply plug everything in :)

y = mx + b

y = (-6)x + (5)

Simplify.

y = -6x + 5

~Hope I helped!~

8 0

3 years ago

Determine the smallest integer value of x in 5x + 3 ≥ 10

Ivanshal [37]

5x + 3 ≥ 10

3 is adding on the left, then it will subtract on the right

5x ≥ 10 -3

5x ≥ 7

5 is multiplying on the left, then it will divide on the right

x ≥ 7/5

x ≥ 1.4

Then, the smallest integer value of x is 2

6 0

1 year ago

Which pair of funtions is not a pair of inverse functions? please help!!

antiseptic1488 [7]

Answer:

$f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}$

Step-by-step explanation:

we know that

To find the inverse of a function, exchange variables x for y and y for x. Then clear the y-variable to get the inverse function.

we will proceed to verify each case to determine the solution of the problem

<u>case A)</u> $f(x)=\frac{x+1}{6} , g(x)=6x-1$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y+1}{6}$

Isolate the variable y

$6x=y+1$

$y=6x-1$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=6x-1$

therefore

f(x) and g(x) are inverse functions

<u>case B)</u> $f(x)=\frac{x-4}{19} , g(x)=19x+4$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y-4}{19}$

Isolate the variable y

$19x=y-4$

$y=19x+4$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=19x+4$

therefore

f(x) and g(x) are inverse functions

<u>case C)</u> $f(x)=x^{5}, g(x)=\sqrt[5]{x}$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=y^{5}$

Isolate the variable y

fifth root both members

$y=\sqrt[5]{x}$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=\sqrt[5]{x}$

therefore

f(x) and g(x) are inverse functions

<u>case D)</u> $f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y}{y+20}$

Isolate the variable y

$x(y+20)=y$

$xy+20x=y$

$y-xy=20x$

$y(1-x)=20x$

$y=20x/(1-x)$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=20x/(1-x)$

$\frac{20x}{1-x}\neq \frac{20x}{x-1}$

therefore

f(x) and g(x) is not a pair of inverse functions

7 0

3 years ago

Read 2 more answers

A square stepping stone has a side length of 10 1/4 inches.

Svetach [21]

Area=2.5

Step-by-step explanation:

area

$area = length \times width$

$area = 10 \times \frac{1}{4}$

8 0

3 years ago

Read 2 more answers

I don't need an answer anymore.

Ghella [55]

Is this a question? Or what is the question if you first said it?

4 0

3 years ago