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Fofino [41]
3 years ago
9

I need help ASAP please

Mathematics
1 answer:
statuscvo [17]3 years ago
6 0

Explanation is in the photo

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Write an equation of the circle with center (2, -9) and radius 3.
KiRa [710]

Answer:

c =  {g}^{2}  +  {f}^{2} +   {r}^{2}  \\ c =  {2}^{2}  +  {( - 9)}^{2}  +  {3}^{2}  \\ c = 94 \\  =  >  \:  {x}^{2}  +  {y}^{2}  - 4x + 18y + 94 = 0

8 0
2 years ago
Alyssa fed her dog 2/3 cup of dog food in the morning and another 5/8 cup in the evening. How much did her dog eat over the cour
kotegsom [21]
1 7/24 is the correct answer I will show you how to get it if needed.
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2 years ago
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If a polynomial has four terms, 3x3 5x 6x2 10, which factoring method can be considered? perfect-square trinomial difference of
Tems11 [23]

The factoring method which can be considered for such a cubic tetranomial expression is; factor by grouping sum of cubes.

<h3>What factoring method can be considered for the polynomial?</h3>

It follows from the task content that the order of the Polynomial is 3 and the polynomial is a tetranomial as it contains 4 terms.

On this note, since 3x³ is not a perfect cube, it follows that the best factorisation method for such a polynomial is; factor by grouping sum of cubes.

Read more on factorisation;

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8 0
2 years ago
Laura’s printer takes 5 minutes to print 85 pages.
evablogger [386]

Answer:

17.

Step-by-step explanation:

<u>Divide 85 by 5 to find the unit rate:</u>

<u />\frac{85}{5} =17

17 represents the amount of pages printed for 1 minute.

5 0
3 years ago
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find the work done by a person pushing a 40 pound box up an incline that is 30 degrees above the horizontal and 100 feet long (i
tankabanditka [31]

The work done in pushing the box is 64000 lb-ft²/s²

<h3>How to calculate the work done by the person?</h3>

Since person pushing a 40 pound box up an incline that is 30 degrees above the horizontal and 100 feet long, the work done, W is

W = mgh where

  • m = mass of box = 40 lb,
  • g = acceleration due to gravity = 32 ft/s² and
  • h = height of incline = LsinФ where
  • L = length of incline = 100 ft and
  • Ф = angle of incline = 30°

So, W = mgh

W = mgLsinФ

So, substituting the values of the variables into the equation, we have

W = mgLsinФ

W = 40 lb × 32 ft/s² × 100 ftsin30°

W = 1280 lb-ft/s² × 100 ft × 0.5

W = 1280 lb-ft/s² × 50 ft

W = 64000 lb-ft²/s²

So, the work done in pushing the box is 64000 lb-ft²/s²

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3 0
2 years ago
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