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Ghella [55]
2 years ago
12

The data shown in the table below can be

Mathematics
1 answer:
kvv77 [185]2 years ago
4 0

Answer:

6: 12

7: 14

8: 16

Step-by-step explanation:

You do the last (y) term given [18] minus the first (y) term [10] given divided by how many terms it takes to get from the last (y) term given minus the first (y) term given [4]. So the equation looks like this:

(18 - 10)/4= 8/4 = 2

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The number of Internet users in Latin America grew from 25.8 million in 2009 to 70.6 million in 2016. Use the geometric mean to
ipn [44]

Answer:

the annual growth rate is 15.47 %

Step-by-step explanation:

Given the data in the question;

Internet users grew from 25.8 million to 70.6 million,

from the year 2009 to the year 2016.

Using geometric mean, Annual growth rate = ?

To determine the average growth rate of a time series using geometric mean, we use the following formula;

r_{geo = [ ( Xₙ / X₀ )^{\frac{1}{n} ] - 1

where Xₙ is the data value of the last year { 70.6 million }

X₀ is the data value for the first year { 25.8 million }

n is the sample size or the time difference, ( 2016 - 2009 = 7 )

so we substitute;

r_{geo =  [ ( 70.6 / 25.8  )^{\frac{1}{7} ] - 1

r_{geo = [ ( 2.736434  )^{\frac{1}{7} ] - 1

r_{geo = [ 1.15466 ] - 1

r_{geo = 0.15466

r_{geo = ( 0.15466 × 100 )%

r_{geo = 15.47 %

Therefore, the annual growth rate is 15.47 %

5 0
2 years ago
Consider the equation 4x2 + 2x = (x + 2)(x − 5)x Match the Property used to create an equation with the same solution set. optio
mel-nik [20]

Factor then solve. Exact Form: x = 0 , 7 + √ 97 2 , 7 − √ 97 2 Decimal Form: x = 0 , 8.42442890 … , − 1.42442890 …

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2 years ago
jana ran the first 3.5 miles of a 5 mile race in 1/3 hour what was the rate in miles per hour for this first part of the race? e
Grace [21]
2.8 1/3 of 3.5 is .7    .7 - 3.5=2.8
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2 years ago
Which measurement statement is correct?
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There are 2 cups in a pint is correct

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2 years ago
I need help with this practice problem solving This is trigonometry from my ACT prep guide
Novay_Z [31]

Take into account, that in general, a cosine function of amplitude A, period T and vertical translation b, can be written as follow:

f(x)=A\cos (\frac{2\pi}{T}x)+b

In the given case, you have:

A = 4

T = 3π/4

b = -3

By replacing you obtain:

\begin{gathered} f(x)=4\cos (\frac{2\pi}{\frac{3\pi}{4}}x)-3 \\ f(x)=4\cos (\frac{8}{3}x)-3 \end{gathered}

Hence, the answer is:

f(x) = 4cos(8/3 x) - 3

6 0
8 months ago
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