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Neko [114]
2 years ago
5

A banana peel weighs 1/12 of the total weight of a banana. If an unpeeled banana balances a peeled banana of the same​ weight, p

lus 11/12 of an​ ounce, how much does the banana weigh with the​ peel?
(NEED HELP ASAP 100PTS + Brainliest)
Mathematics
2 answers:
Advocard [28]2 years ago
7 0

Answer:

11 ounces

Step-by-step explanation:

Suppose, weight of the banana with the​ peel is x ounce.

x-11x/12

As the banana peel weighs  1/12 of the total weight of a banana, so the weight of the peel  1/12 ounce and the weight of a peeled banana11/12 ounce

12/12 ounce= weight 11 ounces

Ilia_Sergeevich [38]2 years ago
4 0

Answer:

11 ounces

Step-by-step explanation:

Unpeeled = X

Peeled = (1 - 1/12)X = (11/12)X

X = (11/12)X + (11/12)

X - (11/12)X = 11/12

(1/12)X = 11/12

X = 11 ounces

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Plz help! Giving a lot of points! :)
monitta
(B) carlos: 920 - 300 = 680
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5 0
2 years ago
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PLEASSSsSEEeeE HeLPpPp
prisoha [69]

Answer:

D = 59t

P = 42t

5 hours after noon, darmian is 17 miles closer to the stadium than paisley

Step-by-step explanation:

At noon, Damian is 383 miles away from the stadium and paisley is 315 miles away from the stadium.

Now, we are told that damians speed is 59 mph while paisley's speed is 42 mph.

At t hours after noon, their distance covered will be;

Damian; D = 59t

Paisley; P = 42t

This is because distance = speed × time

Now, 5 hours after noon, their respective distance covered will be;

D(5) = 59 × 5 = 295 miles

P(5) = 42 × 5 = 210 miles

This means that;

distance of Damian from the stadium is; 383 - 295 = 88 miles

Distance of paisley from the stadium is;

315 - 210 = 105 miles

Difference in their distances to the stadium = 105 - 88 = 17 miles

Thus, 5 hours after noon, darmian is 17 miles closer to the stadium than paisley

4 0
2 years ago
Solve 3x^2=-12x-15 using a quadratic equation with complex solutions
adelina 88 [10]

The complex solution of a quadratic equation are (- 2 + i ) and

(- 2 - i ).

What is Quadratic equation?

An algebraic equation of the second degree is called a quadratic equation.

Given that;

A quadratic equation is;

3x² = -12x - 15

Now, The equation is written as;

3x² + 12x + 15 = 0

Take 3 common, we get;

3 (x² + 4x + 5) = 0

x² + 4x + 5 = 0

Factorize the equation by using Sridharacharya Formula;

x = - 4 ± √4² - 4*1*5 / 2*1

x = -4 ± √16 - 20 / 2

x = - 4 ± √-4 / 2

Since, √-1 = i

x = -4 ± 2i / 2                            

x = - 2 ± i

It gives two values of x as;

x = - 2 + i

And, x = - 2 - i

Hence, The complex solution of a quadratic equation are (- 2 + i ) and

(- 2 - i ).

Learn more about the quadratic equation visit:

brainly.com/question/24334139

#SPJ1

5 0
9 months ago
(b) For a function h(theta)=sin3 theta (Theta is in Radian). <br> Find h(pi/3)<br> Find h(pi/2)
vaieri [72.5K]

Part (i)

Plug in theta = pi/3 to get

h(theta) = sin(3theta)

h(pi/3) = sin(3*pi/3)

h(pi/3) = sin(pi)

h(pi/3) = 0 ... use a calculator or the unit circle

<h3>Answer: 0</h3>

=================================================

Part (ii)

Plug in h = pi/2

h(theta) = sin(3theta)

h(pi/2) = sin(3pi/2)

h(pi/2) = -1

<h3>Answer:  -1</h3>
5 0
3 years ago
2767545 to the nearest ten
vovangra [49]
276550 hope this helps !
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3 years ago
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