Answer:
Step-by-step explanation:
A V-shaped graph is the graph of an absolute value function.
The parent absolute value function is
Among the given options, a V-shaped graph is
This graph is obtained by shifting the parent absolute value function 2 units right.
The correct option is A
Answer:
9.75
Step-by-step explanation:
Answer:
The statement that "the margin of error was given as 
percentage points" means that the population proportion is estimated to be with a certain level of confidence, within the interval 
; where ![\hat{p}[tex] is the sample's proportion. The correct answer is C. The statement indicates that the interval [tex]0.14\pm0.05](https://tex.z-dn.net/?f=%5Chat%7Bp%7D%5Btex%5D%20is%20the%20sample%27s%20proportion.%3C%2Fp%3E%3Cp%3E%20%3C%2Fp%3E%3Cp%3EThe%20correct%20answer%20is%20C.%20The%20statement%20indicates%20that%20the%20interval%20%5Btex%5D0.14%5Cpm0.05)
is likely to contain the true population percentage of people that prefer chocolate pie.
Step-by-step explanation:
The margin of error for proportions is given by the following formula:
Where:
is the critical value that corresponds to the confidence level; the confidence level being 
,
is the sample's proportion of successes,
is the size of the sample.
In this exercise we have that 
and that the margin of error is 0.05.
Therefore if we replace in the formula to calculate the confidence interval we get:
Which means that the true population proportion is estimated to be, with a certain confidence level, within the interval (0.09, 0.19).
Answer:
A=80
B=31
C=64
Step-by-step explanation:
A, 69, and b will equal 180 since it forms a straight line
A+69+b=180
to solve for A we subtract 53+47 from 180 and get 80
80+69+b=180
to get B we subtract 80+69 from 180 and get 31
to get c we add 85+b and subtract it from 180 getting c=64
Answer:
Using tally marks
Step-by-step explanation:
Missing information;
Number of pets are;
3,0,1,4,4,1,2,0,2,2,0,2,0,1,3,1,2,1,1,3
Find;
Ungroups frequency distribution table
Computation:
<u>Number of pets Tally Frequency</u>
0 IIII 4
1 IIIII I 6
2 IIIII 5
3 III 3
4 II 2
