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alexandr1967 [171]
2 years ago
12

HELP PLEASE WILL MARK RIGHT ANSWER BRAINLIEST

Mathematics
1 answer:
lukranit [14]2 years ago
5 0

Answer:

The last answer. The slope 1.8 is positive so it will slope upward from left to right. Since 1.8 is less than 2.5 the slope of the line will be less steep.

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Tucker bought a new speaker priced at $45 and the sales tax is 7%. What is the total cost of the speaker after tax?
OleMash [197]
The total cost is $41.85


Amount Saved = 45 x 7 / 100
Amount Saved = 315 / 100
Amount Saved = $3.15 (answer).
In other words, a 7% discount for a item with original price of $45 is equal to $3.15 (Amount Saved).
Note that to find the amount saved, just multiply it by the percentage and divide by 100.
3 0
2 years ago
Read 2 more answers
The volume of the polyhedron is ______ cm3.
PSYCHO15rus [73]

Answer:

50.80 cm^3

Step-by-step explanation:

the polyhedron is a rectangular pyramid

Volume of a rectangular pyramid = 1/3 x ( width x height x length)

1/3 ( 4 x 5 x 3) = 20 inches

we need to convert inches to cm

1 in = 2.54 cm

20 x 2.54 = 50.80 cm^3

8 0
3 years ago
Solve for x in the equation 2x^2+3x-7=x^2+5x+39
Shalnov [3]
Hey there, hope I can help!

\mathrm{Subtract\:}x^2+5x+39\mathrm{\:from\:both\:sides}
2x^2+3x-7-\left(x^2+5x+39\right)=x^2+5x+39-\left(x^2+5x+39\right)

Assuming you know how to simplify this, I will not show the steps but can add them later on upon request
x^2-2x-46=0

Lets use the quadratic formula now
\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}
x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:} a=1,\:b=-2,\:c=-46: x_{1,\:2}=\frac{-\left(-2\right)\pm \sqrt{\left(-2\right)^2-4\cdot \:1\left(-46\right)}}{2\cdot \:1}

\frac{-\left(-2\right)+\sqrt{\left(-2\right)^2-4\cdot \:1\cdot \left(-46\right)}}{2\cdot \:1} \ \textgreater \  \mathrm{Apply\:rule}\:-\left(-a\right)=a \ \textgreater \  \frac{2+\sqrt{\left(-2\right)^2-4\cdot \:1\cdot \left(-46\right)}}{2\cdot \:1}

Multiply the numbers 2 * 1 = 2
\frac{2+\sqrt{\left(-2\right)^2-\left(-46\right)\cdot \:1\cdot \:4}}{2}

2+\sqrt{\left(-2\right)^2-4\cdot \:1\cdot \left(-46\right)} \ \textgreater \  \sqrt{\left(-2\right)^2-4\cdot \:1\cdot \left(-46\right)}

\mathrm{Apply\:rule}\:-\left(-a\right)=a \ \textgreater \  \sqrt{\left(-2\right)^2+1\cdot \:4\cdot \:46} \ \textgreater \  \left(-2\right)^2=2^2, 2^2 = 4

\mathrm{Multiply\:the\:numbers:}\:4\cdot \:1\cdot \:46=184 \ \textgreater \  \sqrt{4+184} \ \textgreater \  \sqrt{188} \ \textgreater \  2 + \sqrt{188}
\frac{2+\sqrt{188}}{2} \ \textgreater \  Prime\;factorize\;188 \ \textgreater \  2^2\cdot \:47 \ \textgreater \  \sqrt{2^2\cdot \:47}

\mathrm{Apply\:radical\:rule}: \sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b} \ \textgreater \  \sqrt{47}\sqrt{2^2}

\mathrm{Apply\:radical\:rule}: \sqrt[n]{a^n}=a \ \textgreater \  \sqrt{2^2}=2 \ \textgreater \  2\sqrt{47} \ \textgreater \  \frac{2+2\sqrt{47}}{2}

Factor\;2+2\sqrt{47} \ \textgreater \  Rewrite\;as\;1\cdot \:2+2\sqrt{47}
\mathrm{Factor\:out\:common\:term\:}2 \ \textgreater \  2\left(1+\sqrt{47}\right) \ \textgreater \  \frac{2\left(1+\sqrt{47}\right)}{2}

\mathrm{Divide\:the\:numbers:}\:\frac{2}{2}=1 \ \textgreater \  1+\sqrt{47}

Moving on, I will do the second part excluding the extra details that I had shown previously as from the first portion of the quadratic you can easily see what to do for the second part.

\frac{-\left(-2\right)-\sqrt{\left(-2\right)^2-4\cdot \:1\cdot \left(-46\right)}}{2\cdot \:1} \ \textgreater \  \mathrm{Apply\:rule}\:-\left(-a\right)=a \ \textgreater \  \frac{2-\sqrt{\left(-2\right)^2-4\cdot \:1\cdot \left(-46\right)}}{2\cdot \:1}

\frac{2-\sqrt{\left(-2\right)^2-\left(-46\right)\cdot \:1\cdot \:4}}{2}

2-\sqrt{\left(-2\right)^2-4\cdot \:1\cdot \left(-46\right)} \ \textgreater \  2-\sqrt{188} \ \textgreater \  \frac{2-\sqrt{188}}{2}

\sqrt{188} = 2\sqrt{47} \ \textgreater \  \frac{2-2\sqrt{47}}{2}

2-2\sqrt{47} \ \textgreater \  2\left(1-\sqrt{47}\right) \ \textgreater \  \frac{2\left(1-\sqrt{47}\right)}{2} \ \textgreater \  1-\sqrt{47}

Therefore our final solutions are
x=1+\sqrt{47},\:x=1-\sqrt{47}

Hope this helps!
8 0
2 years ago
Read 2 more answers
If x=-1\3 is a zero of a polynomial p(x)=27xcube -axsquare -x+3 then find the value of a
antoniya [11.8K]

Answer:

a = 21

Step-by-step explanation:

If x = h is a zero of a polynomial then f(h) = 0, thus

p(- \frac{1}{3} ) = 27( - \frac{1}{3} )³ - a(- \frac{1}{3} ) - (- \frac{1}{3} ) + 3 = 0, that is

27 (- \frac{1}{27} ) - \frac{1}{9} a + \frac{1}{3} + 3 = 0

- 1 - \frac{1}{9} a + \frac{10}{3} = 0 ( multiply through by 9 to clear the fractions )

- 9 - a + 30 = 0

- a + 21 = 0 ( subtract 21 from both sides )

- a = - 21 ( multiply both sides by - 1 )

a = 21

5 0
2 years ago
9. A simple interest loan with a principal of
8090 [49]

Answer:

437.50

Step-by-step explanation:

Okay so you need to give him 5000 but now its 5875 cuz you waited so just do 875÷2

3 0
2 years ago
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