Answer:
I think it could be modelled by the function I'm not 100 percent sure but i hope it helps
Step-by-step explanation:
Answer:
46
Step-by-step explanation:
By arranging the numbers from least to greatest, you can find the median by locating the central number in the data set.
Answer:
- BDA
- ACD
- QBO
Step-by-step explanation:
BRO,HOW TO UPLOAD PDG
Answer:
y = -
(x - 5)² + 7
Step-by-step explanation:
The equation of a quadratic in vertex form is
y = a(x - h)² + k
where (h, k ) are the coordinates of the vertex and a is a multiplier
Here (h, k ) = (5, 7 ) , then
y = a(x - 5)² + 7
To find a substitute (10, - 3 ) into the equation
- 3 = a(10 - 5)² + 7 ( subtract 7 from both sides )
- 10 = 5²a = 25a ( divide both sides by 25 )
= a , that is
a = - 
y = -
(x - 5)² + 7 ← in vertex form
Answer: 0.0035
Step-by-step explanation:
Given : The readings on thermometers are normally distributed with a mean of 0 degrees C and a standard deviation of 1.00 degrees C.
i.e.
and
Let x denotes the readings on thermometers.
Then, the probability that a randomly selected thermometer reads greater than 2.17 will be :_
![P(X>2.7)=1-P(\xleq2.7)\\\\=1-P(\dfrac{x-\mu}{\sigma}\leq\dfrac{2.7-0}{1})\\\\=1-P(z\leq2.7)\ \ [\because\ z=\dfrac{x-\mu}{\sigma}]\\\\=1-0.9965\ \ [\text{By z-table}]\ \\\\=0.0035](https://tex.z-dn.net/?f=P%28X%3E2.7%29%3D1-P%28%5Cxleq2.7%29%5C%5C%5C%5C%3D1-P%28%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%5Cleq%5Cdfrac%7B2.7-0%7D%7B1%7D%29%5C%5C%5C%5C%3D1-P%28z%5Cleq2.7%29%5C%20%5C%20%5B%5Cbecause%5C%20z%3D%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%5D%5C%5C%5C%5C%3D1-0.9965%5C%20%5C%20%5B%5Ctext%7BBy%20z-table%7D%5D%5C%20%5C%5C%5C%5C%3D0.0035)
Hence, the probability that a randomly selected thermometer reads greater than 2.17 = 0.0035
The required region is attached below .