![\sqrt[3]{\dfrac{-27}{125}} = -\sqrt[3]{\left(\dfrac{3}{5}\right)^{3}}=\dfrac{-3}{5}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cdfrac%7B-27%7D%7B125%7D%7D%20%3D%20-%5Csqrt%5B3%5D%7B%5Cleft%28%5Cdfrac%7B3%7D%7B5%7D%5Cright%29%5E%7B3%7D%7D%3D%5Cdfrac%7B-3%7D%7B5%7D)
The appropriate choice appears to be ...
B. -3/5
Answer:
x = 55
Step-by-step explanation:
For PQ and RS to be parallel then
∠ACQ = ∠RDB ( Alternate exterior angles ), thus
3x - 65 = 2x - 10 ( subtract 2x from both sides )
x - 65 = - 10 ( add 65 to both sides )
x = 55
The given information permits us to calculate the circumference (C) of the wheel as follows

Then (as you said correctly!) the same wheel will move

after 16 rolls.