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PilotLPTM [1.2K]
4 years ago
11

A rectangular box with a volume of 70 ft3 has a square base. find a function that models its surface area s in terms of the leng

th x of one side of its base.
Mathematics
1 answer:
Likurg_2 [28]4 years ago
4 0
Visual of anykind please
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ANSWER PLEASE!!!!!!!!!
stiks02 [169]

Answer:

A. True

B. False

C.True

D. True

E. Sometimes true

F. False

G. True

H. Sometimes true.

Explanation:

If I got it wrong, I will try better next time.

8 0
3 years ago
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Suppose y varies directly with x. If y=6 when y=-2, find x when y=15.
raketka [301]

Answer:

-5

Step-by-step explanation:

8 0
3 years ago
Find the missing dimension of the triangle. A triangle with base labeled b, height labeled 6 feet, and height labeled 14 square
jarptica [38.1K]

Answer:

4.67 feet

Step-by-step explanation:

The computation of missing dimension of the triangle is given below:

As we know that

Area of the triangle = 1 ÷ 2 × base × height

14 = 1 ÷ 2 × base × 6

14 = 3 × base

So, the base is

= 14 ÷ 3

= 4.67 feet

Here we assume the area to be 14 square feet

6 0
3 years ago
Radical of 80 simplified
schepotkina [342]

Answer:

4 √ 5

Step-by-step explanation:

√80

= 4 √ 5 ≈ 8.94

8 0
3 years ago
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I can read a 336-page book in 6 hours. Jayne can read a 144-page book in 3 hours. If I start reading a 5000-page book at noon an
dimulka [17.4K]

Answer:

12:00 am midnight

Step-by-step explanation:

Given;

I can read a 336-page book in 6 hours.

My rate r1 = 336/6 pages per hour = 56 pages per hour

Jayne can read a 144-page book in 3 hours.

Jayne rate r2 = 144/3 = 48 pages per hour

If I start reading a 5000-page book at noon and Jayne starts reading the same book at 10 AM

Taking 10 am as the reference time.

Let x represent the time from 10 am at which they would both be on the same page.

For me;

Since i started by noon; 2 hours after 10 am

Time t1 = x-2

For Jayne;

She started by 10 am

Time t2 = x

For them to be on the same page they must have read the same number of pages;

Number of pages read = rate × time

r1(t1) = r2(t2)

Substituting the values;

56(x-2) = 48(x)

56x - 112 = 48x

x(56-48) = 112

x = 112/(56-48)

x = 14 hours

Since 10 am is the reference, the time would be;

=10 am + x = 10 am + 14 hours

= 24:00

= 12:00 am midnight

8 0
3 years ago
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