Answer:
x = 2
Step-by-step explanation:
Express the ratio in fractional form
=
( cross- multiply )
6x = 12 ( divide both sides by 6 )
x = 2
Will mark brainliest!!! Please helppp!!
1 answer:
You might be interested in
Answer:
○ 3
○ y + ½ = 3(x - 2)
○ Multiply both sides of the equation by 3. The Standard Form of the equation is 12x - 2y = 24.
○ 5x - 3y = 15
○ y = ½x + 5⁄2
Step-by-step explanation:
Find the <em>rate</em><em> </em><em>of</em><em> </em><em>change</em><em> </em>[<em>slope</em>]:
-y₁ + y₂\-x₁ + x₂ = m → (-1, 1) and (-2, -2)
__________________________________________________________
According to the Point-Slope Formula, <em>y - y₁ = m(x - x₁)</em>, all the negative symbols give the OPPOSITE terms of what they really are, so be EXTREMELY CAREFUL inserting this coordinate into the formula with their CORRECT SIGNS:
(2, -½) → y + ½ = 3(x - 2)
__________________________________________________________
We do not want fractions in our Standard Equation, so multiply by the denominator to get rid of it:
-3[4x - ⅔y = 8] → -12x + 2y = -24
** They should have multiplied by -3 instead of 3 because that negative is hooked up to everything in the fraction, but since the exercise gave you 12x - 2y = 24, go with 12x - 2y = 24.
__________________________________________________________
If you would take a look at this graph real closely, you will see that this graph intersects the y-axis and x-axis at ENDPOINTS, so to find the x-intercept, you simply plug in <em>zero</em> for <em>y</em>: 5x = 15, and you will know right away that <em>x</em><em> </em>is set to equal 3, which is what you see in the graph, (3, 0). Now, to find the y-intercept, you simply plug in <em>zero</em><em> </em>for <em>x</em>: -3y = 15, and you will know right away that <em>y</em><em> </em>is set to equal -5, which is what you see on the graph as well, (0, -5). With that being said, you have your answer.
__________________________________________________________
y - 3 = ½(x - 1)
y - 3 = ½x - ½
+ 3 + 3
_____________
y = ½x + 2½
* 2½ = 5⁄2
I am joyous to assist you anytime.