Hello and Good Morning/Afternoon:
<u>Let's take this problem step-by-step:</u>
<u>First off, let's write the line in point-slope form:</u>
- (x₀, y₀) any random point on the line
- 'm' is the value of the slope
<u>Let's calculate the slope:</u>
- (x₁, y₁): any random point on the line ⇒ (-2, -6)
- (x₂,y₂): any random point on the line that is not (x₁, y₁) ⇒ (2, -3)
<u>Now that we found the slope, let's put it into the point-slope form</u>
⇒ we need (x₀, y₀) ⇒ let's use (2,-3)
<u>The equation, however, could also be put into 'slope-intercept form'</u>
⇒ gotten by isolating the 'y' variable to the left
<u>Answer:</u> or 
*<em>Either equations work, put the one that you are the most familiar with</em>
Hope that helps!
#LearnwithBrainly
5/2 is already in its simplest form. You cannot reduce this fraction any further.
<h3>
Answer:</h3>
infinite solutions
<h3>
Step-by-step explanation:</h3>
Add the two equations.
... (-4x) + (y) = (y +3) +(-4x -3)
Add 4x -y to both sides.
... -4x +y +4x -y = -4x +y +4x -y
... 0 = 0 . . . . . true for all values of x (or y)
Both equations describe the same line.
_____
The graph shows the first equation as a red line. The second equation is shown using a "blue dot" texture, so you can see it overlays the red line.
<span>Let's find out the ball's acceleration
V^2 = U^2 + 2as
Where the distance S = 6 feet and U = 45.
Suppose he just took off so V = 0 and we are left with U^2 =2as
(45)^2 = 2a(6)
a = 2025/12 = 168.75 ft/s^2
Also S = ut + 1/2 at^2
Here S = 5ft and U= 0; a = 168.75. So we have 5 = (1/2) * 168.75 * t^2
So we have 5 * 2 = 168.75 t^2
T^2 = âš 10/ 168.75 = 0.00596 = âš0.006
T = 0.0077s</span>
