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deff fn [24]
3 years ago
7

What is the total area of the glass in the pyramid arena? Explain how you got the answer please.

Mathematics
2 answers:
Evgesh-ka [11]3 years ago
8 0

Answer:

A(total) = 528,000 feet^2

Step-by-step explanation:

The slant height of each of the four triangular sides is given and is 440 feet.  The length of the base of each is 600 feet.  We apply the formula for the area of a triangle, which is A = (1/2)(base)(height):

Area of one triangular side:  A = (1/2)(600 feet)(440 feet) = 132,000 feet^2.

The total glass area of the pyramid is thus four times this, or

A(total) = 528,000 feet^2

Blababa [14]3 years ago
5 0

Answer: 888,000

Step-by-step explanation:

Base: 600 x 600 = 360,000

600 x 440 x 2 (there is 4 triangles and 2 makes 1 square. So there is 2 pairs so times 2)= 528,000

360,000 + 528,000= 888,000

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Using finite difference, the answer is cubic. Apologies if I’m wrong

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The Flynns' monthly budget allowed them to spend 5555 for household expenses. During June and July they
cricket20 [7]

Answer:

They have over spent $925

Step-by-step explanation:

Given:

The Monthly amount Flynn's spent on Household  = $555

Amount spent In June and July together = #2035

To Find:

The over spent amount in June and July = ?

Solution:

For a month the budget is $555

According to the budget the amount they should have spent for the month of June and July will be

=> $555 for June  + $555 for July

=> $1110

But they have spent $ 2035 for June and July together

Si the extra amount will be

Amount spent - actual budget amount

=> $2035 - $1110

=> $925

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3 years ago
A baseball is thrown in a parabolic arc. It's position above the ground at a given point in time can be represented by the quadr
SCORPION-xisa [38]

Answer:

The baseball reached 9 feet high above the ground

Step-by-step explanation:

The given quadratic function representing the position of the baseball above ground is p(t) = 1/2·g·t² + v₀·t + p₀

Where;

t ≥ 0

g = -32 ft./sec²

v₀ = The initial velocity

p₀ = The initial position

Given that when the ball is thrown, we have;

The initial, straight up, velocity, v₀ = 16 ft./sec

The initial position, p₀ = 5 ft.

Substituting the above values in the quadratic function representing the position of the baseball above ground, we have;

p(t) = 1/2·(-32)·t² + 16·t + 5 = 16·t - 16·t² + 5

At the maximum point, the rate of change of the height with time = 0, therefore;

dp(t)/dt = 0 = d(16·t - 16·t² + 5)/dt = 16 - 32·t

16 - 32·t = 0

16 = 32·t

t = 16/32 = 0.5 seconds

Therefore, the time takes to reach the maximum height = 0.5 seconds

The height (maximum) reached in 0.5 seconds is given as follows;

h(t) = 16·t - 16·t² + 5, from which we have;

h(0.5) = 16 × 0.5 - 16 × (0.5)² + 5 = 9

Therefore, the height baseball reached = 9 ft. above ground

7 0
3 years ago
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