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kumpel [21]
3 years ago
13

A study of lobster trap placement used a 90​% confidence interval to estimate the mean trap spacing​ (in meters) for the populat

ion of red spiny lobster fishermen fishing in the west coast. How many teams of fisherman would need to be sampled in order to reduce the width of the confidence interval to 6 ​meters? Assume prior knowledge indicates that the trap spacing readings for the population of red spiny lobster taken during a day are approximately normally distributed with a standard deviation of 11.9 meters.'\
Mathematics
1 answer:
prohojiy [21]3 years ago
5 0

Answer:

Step-by-step explanation:

Given that a study of lobster trap placement used a 90​% confidence interval to estimate the mean trap spacing​ (in meters) for the population of red spiny lobster fishermen fishing in the west coast.

Margin of error = 3 metres (half of width of confidence interval)

STd deviation = 11.9 metres

For 90% confidence interval we have margin of error

=1.645(\frac{11.9}{\sqrt{n} } ) = 6\\\sqrt{n} =\\3.2685

n =10.644

=11

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Formulate the situation as a system of inequalities. (Let x represent the number of goats the farmer can raise and y represent t
Firdavs [7]

Answer: He can raise up to 40 goats and 100 llamas.

Step-by-step explanation:

Hi, to answer this question we have to write system of equations with the information given:

The space each goat needs (4) multiplied by the number of goats (x); plus The space each llama needs (10) multiplied by the number of llamas must be less or equal to the acre land available (800)

4x +10y ≤ 800 (acres)

The amount of veterinary care (in $) each  goat needs (110) multiplied by the number of goats (x); plus The  amount of veterinary care   each llama needs (88) multiplied by the number of llamas (y)must be less or equal to the Rancher's budget.(14520)

110x +88y ≤ 14,520 (cost)

Multiplying the first equation by 27.5, and subtracting the second equation to the first one:

110x + 275y ≤22,000

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110x +88y ≤ 14,520

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187y ≤ 7480

y ≤ 7480/187

y ≤ 40

Replacing y in the first equation

4x +10(40) ≤ 800

4x +400 ≤ 800

4x ≤ 800-400

4x ≤ 400

x ≤ 400/4

x ≤ 100

5 0
3 years ago
3. What is the 9th term in the following sequence? 11, 17, 23, 29, . . . (1 point) 47 53 59 65
KatRina [158]
Since the common difference is 6, we can assume that the sequence is arithmetic, with rule
T(n)=6n+5  where T(1)=11
T(9)=6(9)+5=59
5 0
4 years ago
Is my answer correct?
kumpel [21]

Answer:

yes

Step-by-step explanation:

YOU DID IT'S A GOOD DAY

4 0
3 years ago
A group of 25 students want to see a drake concert. Tickets for members of drakes fan club cost $20 and tickets for no members c
Gwar [14]

<span>If you would like to know how many of each type of ticket were sold, you can calculate this using the following two equations:

a ... the number of drakes fan club tickets
s ... the number of no members tickets

$550 = a * $20 + s * $25 ... 550 = 20 * a + 25 * s
a + s = 25 ... a = 25 - s
__________________
</span>550 = 20 * a + 25 * s

<span> 550 = 20 * (25 - s) + 25 * s</span>

550 = 20 * 25 - 20 * s + 25 * s

550 - 20 * 25 = 5 * s

550 - 500 = 5 * s    /5

s = 50 / 5 

s = 10 tickets

<span>a = 25 - s = 25 - 10 = 15 tickets</span>

<span>Result: There were 15 drakes fan club and 10 no members tickets sold.</span>

6 0
4 years ago
There are 8 members on a board of directors. if they must form a subcommittee of 6 members, how many different subcommittees are
Shtirlitz [24]
1. Given a group of n people. There are C(n, r) ways of forming groups of r out of n.

2. Where C(n, r)=\frac{n!}{r!(n-r)!}

3. For example, given {Andy, John, Julia}. We want to pick 2 people to give a gift: we can pick {(Andy, John), (Andy, Julia), (John, Julia)}, so there are 3 ways. So we can list and count.

4. Or we could do this with the formula C(3, 2)=\frac{3!}{2!(1)!}= \frac{3*2*1}{2*1}=3

5. C(8, 6)=\frac{8!}{2!6!}= \frac{8*7*6!}{2*6!}= \frac{8*7}{2}= 4*7=28

So there are C(8,6)=28 ways of chosing 6 out of 8 people to form the subcommittees. <span />
5 0
3 years ago
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