Answer: He can raise up to 40 goats and 100 llamas.
Step-by-step explanation:
Hi, to answer this question we have to write system of equations with the information given:
The space each goat needs (4) multiplied by the number of goats (x); plus The space each llama needs (10) multiplied by the number of llamas must be less or equal to the acre land available (800)
4x +10y ≤ 800 (acres)
The amount of veterinary care (in $) each goat needs (110) multiplied by the number of goats (x); plus The amount of veterinary care each llama needs (88) multiplied by the number of llamas (y)must be less or equal to the Rancher's budget.(14520)
110x +88y ≤ 14,520 (cost)
Multiplying the first equation by 27.5, and subtracting the second equation to the first one:
110x + 275y ≤22,000
-
110x +88y ≤ 14,520
____________
187y ≤ 7480
y ≤ 7480/187
y ≤ 40
Replacing y in the first equation
4x +10(40) ≤ 800
4x +400 ≤ 800
4x ≤ 800-400
4x ≤ 400
x ≤ 400/4
x ≤ 100
Since the common difference is 6, we can assume that the sequence is arithmetic, with rule
T(n)=6n+5 where T(1)=11
T(9)=6(9)+5=59
Answer:
yes
Step-by-step explanation:
YOU DID IT'S A GOOD DAY
<span>If you would like to know how many of each type
of ticket were sold, you can calculate this using the following two
equations:
a ... the number of drakes fan club tickets
s ... the number of no members tickets
$550 = a * $20 + s * $25 ... 550 = 20 * a + 25 * s
a + s = 25 ... a = 25 - s
__________________
</span>550 = 20 * a + 25 * s
<span>
550 = 20 * (25 - s) + 25 * s</span>
550 = 20 * 25 - 20 * s + 25 * s
550 - 20 * 25 = 5 * s
550 - 500 = 5 * s /5
s = 50 / 5
s = 10 tickets
<span>a = 25 - s = 25 - 10 = 15 tickets</span>
<span>Result: There were 15 drakes fan club and 10 no members tickets sold.</span>
1. Given a group of n people. There are C(n, r) ways of forming groups of r out of n.
2. Where C(n, r)=

3. For example, given {Andy, John, Julia}. We want to pick 2 people to give a gift: we can pick {(Andy, John), (Andy, Julia), (John, Julia)}, so there are 3 ways. So we can list and count.
4. Or we could do this with the formula C(3, 2)=

5. C(8, 6)=

So there are C(8,6)=28 ways of chosing 6 out of 8 people to form the subcommittees. <span />