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2 years ago

Please someone help me. Im giving brainliest!

Mathematics

2 answers:

ArbitrLikvidat [17]2 years ago

5 0

Answer:

To solve the equation: First, subtract 9 from both sides of the equation. Second, divide both sides of the equation by -10

Step-by-step explanation:

We are subtracting from both sides because we need to do the inverse, and the inverse of adding 9 is subtracting it.

Same with the -10. We need to do the inverse, and the inverse of multiplying by -10 is dividing by it.

Arada [10]2 years ago

4 0

Answer:

First: Subtract 9 from both sides of the equation. Second: Divide both sides of the equation by -10

Step-by-step explanation:

because 9 is positive, to get rid of it you need to subtract it.

after than, you would get -10x = -30

you would then divide it by -10 because you need to get x by itself

x = -3

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Pls please help me ASAP!!!

oksian1 [2.3K]

Answer:

z = 0

Step-by-step explanation:

3 (z + 7) = 21

3z + 21 = 21

3z = 0

z = 0

8 0

2 years ago

What is the minimum value of the function g(x) = x2 - 6x – 12?<br> -21<br> 3-21<br> 3<br> 3+21

balandron [24]

Answer:

- 21

Step-by-step explanation:

The minimum value occurs at the vertex of the function

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

To obtain this form use the method of completing the square

Given

f(x) = x² - 6x - 12

add/ subtract ( half the coefficient of the x- term)² to x² - 6x

f(x) = x² + 2(- 3)x + 9 - 9 - 12

= (x - 3)² - 21

with vertex = (3, - 21 )

The minimum is the value of k, that is minimum value = - 21

4 0

3 years ago

PLEASe HELP I DONT WANT TO WASTE MY POINTS

QveST [7]

Answer:

4 or 5

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

0.7 (3s + 4)-1.1s = 7.9

vichka [17]

Answer:

s = 5.1

Step-by-step explanation:

$0.7 (3s + 4)-1.1s = 7.9\\$

Multiply both sides of the equation by 10

$0.7\left(3s+4\right)\cdot \:10-1.1s\cdot \:10=7.9\cdot \:10\\\\= 7\left(3s+4\right)-11s=79\\$

Expand

$\mathrm{Expand\:}7\left(3s+4\right)-11s:\\\quad 10s+28$

Subtract 28 from both sides

$10s+28-28=79-28$

Simplify

$10s=51$

Divide both sides of the equation by 10

$\frac{10s}{10}=\frac{51}{10}$

Simplify

$s=\frac{51}{10}\\\\Decimal = 5.1$

3 0

2 years ago

Read 2 more answers

What is the eighth term in the sequence x+3, - 2x^2 - 6x, 4x^3 +12x^2

Anastasy [175]

Answer:

$a_8=-128x^8-384x^7$

Step-by-step explanation:

The terms of the sequence are:

$x+3,-2x^2-6x,4x^3+12x^2,...$

We can rewrite the terms in factored form to get;

$x+3,-2x(x+3),4x^2(x+3),...$

We can see that the subsequent terms are obtained by multiplying the previous term by $-2x$ . This is called the common ratio.

Therefore the first term of this geometric sequence is $a_1=x+3$ and the common ratio is $r=-2x$ .

The nth term of a geometric sequence is given by: $a_n=a_1(r^{n-1})$ .

Let us substitute the first term, the common ratio, and $n=8$ to obtain:

$a_8=(x+3)(-2x)^{8-1}$

$a_8=(x+3)(-2x)^{7}$

$a_8=-128x^7(x+3)$

$a_8=-128x^8-384x^7$

3 0

3 years ago