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Mathematics

2 answers:

Nadya [2.5K]3 years ago

3 0

Line 1 and Line 2 are perpendicular because line 2 has a slope of 5/3 opposite of Line 1’s slope of 3/5

Line 1 and 3 are perpendicular same reason as above

Line 2 and 3 are parallel because the have the same slope of 5/3

tekilochka [14]3 years ago

3 0

What ye hcjjdjdjdmdjdjfkf

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Sneha has 27 coins worth $1.48 in hear jar consisting of dimes, nickels, and pennies. If she then removes 8 of each type of coin

Morgarella [4.7K]

Answer:

Step-by-step explanation:

5 0

3 years ago

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G.SRT.1 In the coordinate plane, quadrilateral ABCD has vertices A (1, 1), * 1 point B (5,1), C (5,9), and D (1, 9). Quadrilater

Natalka [10]

Based on the vertices of quadrilateral ABCD and Quadrilateral FGHJ, A. The scale factor is 1/2, and the center of dilation is point A.

<h3>What is the scale factor?</h3>

First, note the vertices of Quadrilateral FGHJ:

F(1,1) G(3 ,1) J (1 , 5) H(3 , 5)

Find the lengths of the sides of both quadrilaterals:

FG = (3, 1) - (1, 1) AB = (5,1) - (1, 1)

= (2,0) = (4, 0)

FH = (3, 5) - (1, 1) AC = (5,9) - (1, 1)

= (2,4) = (4, 8)

AB is twice the size of FG.

AC is twice the size of FH

This shows that quadrilateral FGHJ is 1/2 the size of quadrilateral ABCD.

Find out more on dilation at brainly.com/question/10253650.

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4 0

2 years ago

The area of a blackboard is 1 1 third square yards. A poster's area is 8 over 9 square yards. What is the unit rate of the black

Darya [45]

Step-by-step explanation:

Given that,

The area of a blackboard is $1\dfrac{1}{3}=\dfrac{4}{3}\ \text{yards}^2$

The area of poster is $\dfrac{8}{9}\ \text{yards}^2$

We need to find the unit rate of the blackboard's area to the poster's area. So, it can be calcualted by dividing blackboard's area to the poster's area.

So,

$\dfrac{\dfrac{4}{3}}{\dfrac{8}{9}}=\dfrac{4}{3}\times \dfrac{9}{8}\\\\=1.5$