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cestrela7 [59]
4 years ago
7

Can someone please help me with that one problem!

Mathematics
1 answer:
maks197457 [2]4 years ago
3 0

Answer:

AAS method can be used to prove that the two triangles are congruent.

Step-by-step explanation:

According to the question for the two triangles one pair of opposite angles are equal. One another pair of angles are equal for the two and one pair of sides are also equal of the two.

Hence, the two given triangles are congruent by AAS rule.

Hence, AAS method can be used to prove that the two triangles are congruent.

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Which of the following polynomials has a remainder of 24 when divided by x+2?
Bad White [126]

Option C is the correct choice   -2x^4+4x^2+3x-2,

Remainder of a polynomial by substitution

For a polynomial f(x) to give a remainder of 24 when divided by x + 2:

f(-2) = 24

By testing, substitute x = -2 into the equation -2x^4+4x^2+3x-2

f(x) = -2x^3+4x^2+3x-2\\\\f(-2)=-2(-2)^3+4(-2)^2+3(-2)-2\\\\f(-2)=-2(-8)+4(4)-6-2\\\\f(-2)=16+16-8\\\\f(-2)=32-8\\\\f(-2)=24

Since f(-2) = 24 when x = -2 is substituted into  -2x^4+4x^2+3x-2, then  -2x^4+4x^2+3x-2 has a remainder of 24 when divided by x+2

Learn more on remainder of a polynomial here: brainly.com/question/24202892

#SPJ1

5 0
2 years ago
Pls answer this question cuz i don't know what is the answer on this one
Sveta_85 [38]

Answer:

12.D

13.C

14.A

15.B

16.A

17.B

18.D

19.A

20.A

and hey I don't know the answer to 11 th question as I don't know much about miles

PS: Have a nice day :)

6 0
3 years ago
Read 2 more answers
Can someone help me with #8
snow_tiger [21]

Answer:

b)

Step-by-step explanation:

4 0
3 years ago
A company produces a certain product, and each unit of this product may have 3 different types of defects. Let Di, D2,Ds represe
Stella [2.4K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a) 0.88

b) 0.02

c) 0.01

d) 0.99

Step-by-step explanation:

Step one: State the given parameters

            P(D_{1} ) = 0.12                                   P(D_{2} ) = 0.07

           P(D_{3} ) = 0.05                                    P (D_{1} U D_{2} ) = 0.13

          P(D_{1}n D_{2}n D_{3}) = 0.01                        P(D_{1} U D_{3}) = 0.14

Step 2 : Obtain the probability that a unit does not have a type 1 defect

         P(\frac{}{D_{1} }) =  1 -P(D_{1} )

                    = 1 - 0.12

                    = 0.88  

Step 3 : Obtain the probability that a unit has both type 2 and 3 defect?

          The probability of the unit having both type 2 and type 3 defect is denoted as P(D_{2} n D_{3} )

   This is calculated as

                    P(D_{2}n D_{3}) =P(D_{2} ) + P(D_{3}) - P(D_{2} U D_{3})\\\\                          = 0.07 + 0,05 - 0.13

                    =   0.02

Therefore P(D_{2} n D_{3} ) = 0.02

Step 4 : Obtain the probability that the unit has both a type 2 and type 3 ,but not a type 1 defect

                  Let P(\frac{}{D_{1}} n D_{2} n D_{3} ) denote the  probability that the unit has both a type 2 and type 3 ,but not a type 1 defect.

This can be calculated as follows :

                      P(\frac{}{D_{1}} n D_{2} n D_{3} ) = P(D_{2} n D_{3}) - P(D_{1} n D_{2}nD_{3})

                                               =   0.02 - 0.01

                                               =  0.01

Step 4 : Obtain the probability that a unit has at most two defects

               P(at most 2 defects)  = 1 - P(all three defects)

                                                  = 1- P(D_{1} n D_{2}nD_{3})

                                                  =  1 - 0.01

                                                  = 0.99

7 0
3 years ago
Find the product. Simplify if possible -1/3 x (8 1/7)
gladu [14]
- 1/3 × 8 1/7 = - 2 5/7

~Hope this helped!~

4 0
3 years ago
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