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RideAnS [48]
3 years ago
6

For each value of x, determine whether it is a solution to x> 8. Is it a solution?

Mathematics
1 answer:
Anni [7]3 years ago
3 0

Answer:

what are the values of X?

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how many bricks can my truck carry in a full load if each brick weighs 4 pounds 14 ounces and my truck can carry a 3/4 ton load​
aleksklad [387]

Answer:

The number of bricks a truck can carry in full load is 308 .

Step-by-step explanation:

Given as :

The weight of each brick = 4 pounds and 14 ounce

The total load a truck can carry = \dfrac{3}{4}  tons

Let The number of bricks truck can carry = n bricks

<u>Now, According to question</u>

∵ 1 ounce = 0.0625 pounds

∴ 14 ounce = 0.0625 × 14 = 0.875 pounds

So, Total weight of each brick = 4 pounds + 0.875 pounds = 4.875 pounds

<u>Again</u>

∵ 1 pound = 0.0005 tons

∴ 4.875 pounds =  0.0005 × 4.875 = 0.0024375 tons

<u>Now, Again</u>

The total load a truck can carry = \dfrac{3}{4} tons = 0.75 tons

And The weight of each brick = 0.0024375 tons

So, The number of bricks = \dfrac{\textrm total load a truck can carry}{\textrm Total weight of each brick}

I.e n = \dfrac{0.75}{0.0024375}

∴ n = 307.69 ≈ 308

So, The number of bricks can truck carry = n = 308

Hence, The number of bricks a truck can carry in full load is 308 . Answer

7 0
3 years ago
Chris tells Adam that the decimal value of − 1 1/3 is not a repeating decimal. Is Chris correct?
Verdich [7]
Chris is wrong since - \frac{11}{3} =-3.666666666666
7 0
3 years ago
Read 2 more answers
A sensor output was acquired for 32 seconds at a rate of 200 Hz and spectral analysis was performed using FFT. If the data set w
VashaNatasha [74]

Complete Question

A sensor output was acquired for 32 seconds at a rate of 200 Hz and spectral analysis was performed using FFT. If the data set was split into 5 segments (each 6.4 seconds long), what is the resulting:

a)F minimum

b) F maximum

c) Frequency resolution

Answer:

a) Fmax=100Hz

b) Fmin=0Hz

c) F_r=0.0313

Step-by-step explanation:

From the question we are told that:

Time t=32sec

FrequencyF=200Hz

Segments \mu=5

Generally the equation for Frequency Range is mathematically given by

Fmax=\frac{F}{2}

Fmax=100Hz

Therefore

a) Fmax=100Hz

b) Fmin=0Hz

c)

Generally the equation for Frequency Resolution is mathematically given by

F_r=\frac{F}{N}

Where

N=The Total dat points

N=Sampling Frequency *Time

N=200*32

N=6400

Therefore

F_r=\frac{200}{6400}

F_r=0.0313

6 0
3 years ago
Drag the tiles to the correct boxes to complete the pairs.
Shalnov [3]

Answer:

its 29

Step-by-step explanation:

6 0
3 years ago
Solve for a.
muminat

A. Because you would have to subtract C to isolate a by itself

8 0
3 years ago
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