For each value of x, determine whether it is a solution to x> 8.<br> Is it a solution?

A firm has the marginal-demand function where D(x)=-1400x÷√25-x² is the number of units sold at x dollars per unit. Find the dem

borishaifa [10]

The equation of the demand function is D(x) = 1400√(25-x²) + 11400

<h3>How to determine the demand function?</h3>

From the question, we have the following parameters that can be used in our computation:

Marginal demand function, D'(x) = -1400x÷√25-x²

Also, we have

D = 17000, when the value of x = 3

To start with, we need to integrate the marginal demand function, D'(x)

So, we have the following representation

D(x) = 1400√(25-x²) + C

Recall that

D = 17000 at x = 3

So, we have

17000 = 1400√(25-3²) + C

Evaluate

17000 = 5600 + C

Solve for C

C = 17000 - 5600

So, we have

C = 11400

Substitute C = 11400 in D(x) = 1400√(25-x²) + C

D(x) = 1400√(25-x²) + 11400

Hence, the function is D(x) = 1400√(25-x²) + 11400

Read more about demand function at

brainly.com/question/24384825

#SPJ1

3 0

1 year ago

A dinner for two at the local seafood restaurant cost

Vlad [161]

Answer:

63.38

Step-by-step explanation:

(49.90)(20%)(6%)

20%= $9.98

49.90+9.98 =59.80

(59.80)(6%)

6%= $3.58

59.80+3.58=63.38

8 0

2 years ago

Kim will say 50% in she opens a credit card she wants to buy a jacket for 120 what will be her savings

Maurinko [17]

Answer:

Kims savings will be $60.

Step-by-step explanation:

120 * .50 = 60

7 0

3 years ago

PLEASE HELP ME PLEASE??

BigorU [14]

Answer:

Table A is correct

Step-by-step explanation:

All you have to do is multiply the hours by 5 to get the answer.

Table B is adding not multiplying.

<em>Can I please have BRAINLIEST?</em>

4 0

3 years ago

A professor finds that the average SAT score among all students attending his college is 1150 ± 150 (μ ± σ). He polls his class

solniwko [45]

Answer:

Step-by-step explanation

Hello!

Be X: SAT scores of students attending college.

The population mean is μ= 1150 and the standard deviation σ= 150

The teacher takes a sample of 25 students of his class, the resulting sample mean is 1200.

If the professor wants to test if the average SAT score is, as reported, 1150, the statistic hypotheses are:

H₀: μ = 1150

H₁: μ ≠ 1150

α: 0.05

$Z= \frac{X[bar]-Mu}{\frac{Sigma}{\sqrt{n} } } ~~N(0;1)$

$Z_{H_0}= \frac{1200-1150}{\frac{150}{\sqrt{25} } } = 1.67$

The p-value for this test is 0.0949

Since the p-value is greater than the level of significance, the decision is to reject the null hypothesis. Then using a significance level of 5%, there is enough evidence to reject the null hypothesis, then the average SAT score of the college students is not 1150.

I hope it helps!

7 0

3 years ago

For each value of x, determine whether it is a solution to x> 8. Is it a solution?