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3 years ago

14

License plates in a particular state display 3letters followed by 3numbers. how many different license plates can be manufacture

d for this state?

1 answer:

mixas84 [53]3 years ago

3 0

there are 26 possible letters to choose from and there are 3 letters

there are 10 possible numbers to choose from and there are 3 numbers

combinations = 26 x 26 x 26 x 10 x 10 x 10 = 17,576,000

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Is -4 an even or odd numnber?

rewona [7]

Answer:

An even number

Step-by-step explanation:

Integers which are multiples of 2, are even numbers.

Integers which aren't multiples of 2, are odd numbers.

As integers can be positive and negative both, odd and even numbers also can be positive and negative.

7 0

3 years ago

If a and b represent numbers, which of the following statements represents the commutative property of multiplication?

Gemiola [76]

The commutative property of multiplication states that the numbers can be multiplied in any order.

a+b = b+a : Commutative property of addition

a*b = b*a : Commutative property of multiplication

a+0=a : Additive identity property

a*1 =a : Multiplicative identity property

Answer : a*b =b*a

7 0

3 years ago

Read 2 more answers

Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S. In other words, find the flux of

tresset_1 [31]

Because I've gone ahead with trying to parameterize $S$ directly and learned the hard way that the resulting integral is large and annoying to work with, I'll propose a less direct approach.

Rather than compute the surface integral over $S$ straight away, let's close off the hemisphere with the disk $D$ of radius 9 centered at the origin and coincident with the plane $y=0$ . Then by the divergence theorem, since the region $S\cup D$ is closed, we have

$\displaystyle\iint_{S\cup D}\vec F\cdot\mathrm d\vec S=\iiint_R(\nabla\cdot\vec F)\,\mathrm dV$

where $R$ is the interior of $S\cup D$ . $\vec F$ has divergence

$\nabla\cdot\vec F(x,y,z)=\dfrac{\partial(xz)}{\partial x}+\dfrac{\partial(x)}{\partial y}+\dfrac{\partial(y)}{\partial z}=z$

so the flux over the closed region is

$\displaystyle\iiint_Rz\,\mathrm dV=\int_0^\pi\int_0^\pi\int_0^9\rho^3\cos\varphi\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi=0$

The total flux over the closed surface is equal to the flux over its component surfaces, so we have

$\displaystyle\iint_{S\cup D}\vec F\cdot\mathrm d\vec S=\iint_S\vec F\cdot\mathrm d\vec S+\iint_D\vec F\cdot\mathrm d\vec S=0$

$\implies\boxed{\displaystyle\iint_S\vec F\cdot\mathrm d\vec S=-\iint_D\vec F\cdot\mathrm d\vec S}$

Parameterize $D$ by

$\vec s(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec k$

with $0\le u\le9$ and $0\le v\le2\pi$ . Take the normal vector to $D$ to be

$\vec s_u\times\vec s_v=-u\,\vec\jmath$

Then the flux of $\vec F$ across $S$ is

$\displaystyle\iint_D\vec F\cdot\mathrm d\vec S=\int_0^{2\pi}\int_0^9\vec F(x(u,v),y(u,v),z(u,v))\cdot(\vec s_u\times\vec s_v)\,\mathrm du\,\mathrm dv$

$=\displaystyle\int_0^{2\pi}\int_0^9(u^2\cos v\sin v\,\vec\imath+u\cos v\,\vec\jmath)\cdot(-u\,\vec\jmath)\,\mathrm du\,\mathrm dv$

$=\displaystyle-\int_0^{2\pi}\int_0^9u^2\cos v\,\mathrm du\,\mathrm dv=0$

$\implies\displaystyle\iint_S\vec F\cdot\mathrm d\vec S=\boxed{0}$

8 0

3 years ago

Please help me with this question <br><br> image attached

user100 [1]

I think the answer is 24

3 0

3 years ago

Read 2 more answers

Solve<br> 2(2x + 1) = 3(x - 4)

k0ka [10]

Step-by-step explanation:

2(2x + 1) = 3(x - 4)

4x+2=3x-12

4x-3x=--12-2

x=14

6 0

2 years ago