Answer:
Mate im sorry for replying here but i need points to ask a question.
The arc length of the semicircle is 5π units
<h3>Calculating length of an arc</h3>
From the question, we are to calculate the arc length of the semicircle
Arc length of a semicircle = 1/2 the circumference of the circle
∴ Arc length of a semicircle = 1/2 × 2πr
Arc length of a semicircle = πr
Where r is the radius
From the given information,
r = 5
∴ Arc length of the semicircle = 5 × π
Arc length of the semicircle = 5π units
Hence, the arc length of the semicircle is 5π units
Learn more on Calculating length of an arc here: brainly.com/question/16552139
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(7 / 2 ) / 100
3.5 / 100
0.035
So your answer is 0.035
The transformed equation y = -(x - 2)^2 - 3 compared to the parent function involves translating the parent function to the right by 2 units, reflecting the function across the y-axis and translating the function 3 units down
<h3>How to compare the function to its parent function?</h3>
The equation of the transformed function is given as:
y = -(x - 2)^2 - 3
While the equation of the parent function is given as
y = x^2
Start by translating the parent function to the right by 2 units.
This is represented as:
(x, y) = (x - 2, y)
So, we have:
y = (x - 2)^2
Next, reflect the above function across the y-axis
This is represented as:
(x, y) = (-x, y)
So, we have:
y = -(x - 2)^2
Lastly, translate the above function 3 units down
This is represented as:
(x, y) = (x, y - 3)
So, we have:
y = -(x - 2)^2 - 3
Hence, the transformed equation y = -(x - 2)^2 - 3 compared to the parent function involves translating the parent function to the right by 2 units, reflecting the function across the y-axis and translating the function 3 units down
Read more about function transformation at:
brainly.com/question/8241886
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