HELP ME WITH THIS PLEASE! What is the equation? OR GROWTH RATE

Mathematics

2 answers:

balu736 [363]3 years ago

8 0

To start, the first thing you need to do is to find the slope of your x and y values, or in other words, your rate of change. To do this, use the slope intercept formula or (y2-y1)/(x2-x1) and you can use any two pairs of x and y values.

Using the x and y values of (2, 96) and (3, 76.80), plug the values into the slope intercept formula. This would look like this:
(76.80-96)/(3-2)

When you simplify, you should get -19.2/1 or simply -19.2 as your slope.

Then, using the linear equation y=mx+b, plug in a coordinate point into the x and y variables and plug your slope into the m value in order to solve for the value of your y-intercept, or b.
This would look like this:
96=-19.2(2)+b

When you simplify, you will get 96=-38.4+b and when you solve for b, you get that b=134.4

Now that you have your slope and your y-intercept, you can conclude that the equation to this input/output chart would be
y=-19.2x+134.4

Gwar [14]3 years ago

7 0

It would help if you would post the complete question not just a few points in a table. Without all the information provided in the question ( initial value??); I can not be certain of the solution. Looking at the table, you can tell the rate is not constant, it changes between points. The data best fits an exponential decay graph. When plotted in excel it gives the equation:
$y = 150 e^{-0.223x}$

with a perfect R² = 1
This equation shows that whatever this data represents started at 150 and exponentially decayed/decreased at a rate of -0.223

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Help me please by solving and showing the steps:)

Lorico [155]

Answer:

$-\frac{3\sqrt[3]{t} }{2}$

Step-by-step explanation:

1: Write g(t) as y, resulting in $y=-\frac{8}{27}t^3$

2: Interchange the variables y and t, resulting in $t=-\frac{8}{27}y^3$

3: Multiply both sides by 27, resulting in $27t=-8y^3$

4: Divide both sides by -8, resulting in $-\frac{27t}{8}=y^3$

5: Find the cube root of both sides, resulting in $\sqrt[3]{-\frac{27t}{8} }=y$

6: Apply a radical rule, resulting in $-\sqrt[3]{\frac{27t}{8} } =y$

7: Apply another radical rule, resulting in $-\frac{\sqrt[3]{27t} }{\sqrt[3]{8} } =y$

8: Simplify the denominator, resulting in $-\frac{\sqrt[3]{27t} }{2} =y$

9: Apply yet another radical rule, resulting in $-\frac{\sqrt[3]{27}\sqrt[3]{t} }{2} =y$

10: Simplify $\sqrt[3]{27}$ , resulting in $-\frac{3\sqrt[3]{t} }{2} =y$

3 0

3 years ago

7.60. When Paul crossed the finish line of a 60-meter race, he was ahead of Robert by 10 meters and ahead of Sam by 20 meters. S

Lelechka [254]

Answer:

The number of meters Robert will beat Sam is 12 meters.

Step-by-step explanation:

Given:

When Paul crossed the finish line of a 60-meter race, he was ahead of Robert by 10 meters and ahead of Sam by 20 meters. Suppose Robert and Sam continue to race to the finish line without changing their rates of speed.

Find:

the number of meters by which Robert will beat Sam

Step 1 of 1

When Paul finishes, Robert has run 60-10=50 meters and Sam has run 60-20=40 meters.

Therefore, when Robert and Sam run for the same amount of time, Sam covers $\frac{40}{50}=\frac{4}{5}$ of the distance that Robert covers. So, while Robert runs the final 10 meters of the race, Sam runs $\frac{4}{5} \cdot 10=8$ meters.