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GalinKa [24]
2 years ago
13

Solve for x. Show each step of the solution. 2.5(4-x)+12=21-4(2.5x+7)

Mathematics
1 answer:
erastova [34]2 years ago
8 0

Answer:

x=-58/15

Step-by-step explanation:

distribute first 10-2.5x+12=21-10x-28

Simplify(add the numbers) 22-2.5x=-7-10x

move the variable to the left side 22-2.5x+10x=-7

move the constant to the right side -2.5x+10x=-7-22

simplify like terms 7.5x=-29

divide by 7.5                       x=-58/15

alternate forms are x=-3 13/15                or  x=-3.86

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Jessica is measuring two line segments. The first line segment is 30 cm long. The second line segment is 500 mm long. How long a
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80 cm

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Suppose we have 3 cards identical in form except that both sides of the first card are colored red, both sides of the second car
Nikolay [14]

Answer:

probability that the other side is colored black if the upper side of the chosen card is colored red = 1/3

Step-by-step explanation:

First of all;

Let B1 be the event that the card with two red sides is selected

Let B2 be the event that the

card with two black sides is selected

Let B3 be the event that the card with one red side and one black side is

selected

Let A be the event that the upper side of the selected card (when put down on the ground)

is red.

Now, from the question;

P(B3) = ⅓

P(A|B3) = ½

P(B1) = ⅓

P(A|B1) = 1

P(B2) = ⅓

P(A|B2)) = 0

(P(B3) = ⅓

P(A|B3) = ½

Now, we want to find the probability that the other side is colored black if the upper side of the chosen card is colored red. This probability is; P(B3|A). Thus, from the Bayes’ formula, it follows that;

P(B3|A) = [P(B3)•P(A|B3)]/[(P(B1)•P(A|B1)) + (P(B2)•P(A|B2)) + (P(B3)•P(A|B3))]

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P(B3|A) = [⅓×½]/[(⅓×1) + (⅓•0) + (⅓×½)]

P(B3|A) = (1/6)/(⅓ + 0 + 1/6)

P(B3|A) = (1/6)/(1/2)

P(B3|A) = 1/3

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3 years ago
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