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olasank [31]
2 years ago
7

Order these numbers from least to greatest 1/5 0.5 0.05 0.23 1/3

Mathematics
1 answer:
rjkz [21]2 years ago
3 0
0.05
1/5 (0.2)
0.23
1/3 (0.33)
0.5
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xxTIMURxx [149]
(-3)2+6(-3)(4) is -63
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Read 2 more answers
(7 + 7i)(2 − 2i)
Ostrovityanka [42]

The complex number  -7i into trigonometric form is 7 (cos (90) + sin (90) i) and  3 + 3i in trigonometric form is 4.2426 (cos (45) + sin (45) i)

<h3>What is a complex number?</h3>

It is defined as the number which can be written as x+iy where x is the real number or real part of the complex number and y is the imaginary part of the complex number and i is the iota which is nothing but a square root of -1.

We have a complex number shown in the picture:

-7i(3 + 3i)

= -7i

In trigonometric form:

z = 7 (cos (90) + sin (90) i)

= 3 + 3i

z = 4.2426 (cos (45) + sin (45) i)

\rm 7\:\left(cos\:\left(90\right)\:+\:sin\:\left(90\right)\:i\right)4.2426\:\left(cos\:\left(45\right)\:+\:sin\:\left(45\right)\:i\right)

\rm =7\left(\cos \left(\dfrac{\pi }{2}\right)+\sin \left(\dfrac{\pi }{2}\right)i\right)\cdot \:4.2426\left(\cos \left(\dfrac{\pi }{4}\right)+\sin \left(\dfrac{\pi }{4}\right)i\right)

\rm 7\cdot \dfrac{21213}{5000}e^{i\dfrac{\pi }{2}}e^{i\dfrac{\pi }{4}}

\rm =\dfrac{148491\left(-1\right)^{\dfrac{3}{4}}}{5000}

=21-21i

After converting into the exponential form:

\rm =\dfrac{148491\left(-1\right)^{\dfrac{3}{4}}}{5000}

From part (b) and part (c) both results are the same.

Thus, the complex number  -7i into trigonometric form is 7 (cos (90) + sin (90) i) and  3 + 3i in trigonometric form is 4.2426 (cos (45) + sin (45) i)

Learn more about the complex number here:

brainly.com/question/10251853

#SPJ1

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2 years ago
Help me preety please
maksim [4K]

Answer: $ 2.55

Step-by-step explanation:

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Johnathan makes $24 in 6 hours, so how much would he make in 8 hours
suter [353]
$24 in 6 hours.

6 hours = $24

1 hour would be:  $24/6 = $4

8 hours would then be:      $4 * 8 = $32.

So he would make $32 in 8 hours.

Hope this explains it.
7 0
3 years ago
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