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Sav [38]
3 years ago
6

PLEASE PLEASE HELP, ILL GIVE BRAINLIEST OR HOWEVERYOU SPELL IT, THIS HAS 40 POINTS SO PLEASE

Mathematics
1 answer:
aleksley [76]3 years ago
3 0

Answer:

x=-1,2,-3   the roots (zeros) are the x values were the graph

You might be interested in
Simplify the expression p(p^-7*q^3)^-2*q^-3<br> A.p/q^3<br> B.p^15/q^9<br> C.1/(p^9*q^2<br> D.p^14*q
Alenkinab [10]

Answer:

B.p^15/q^9

Step-by-step explanation:

p(p^-7•q^3)^-2•q^-3

answer: B. p^15/q^9

3 0
3 years ago
Sketch the graph of each equation. y=-2x+1
Allushta [10]

Step-by-step explanation:

y=-2x+1 so we say (-2x+1)

we flip the equation by saying

-2x+1 -1=y+-1

-2x=y-1

Divide both sides by -2

-2÷-1 = y-1÷-2

so x=-1÷2 y=+1÷2

5 0
1 year ago
A probability experiment is conducted in which the sample space of the experiment is upper s equals startset 4 comma 5 comma 6 c
olchik [2.2K]
The correct question statement is:

A probability experiment is conducted in which the sample space of the experiment is S = {4,5,6,7,8,9,10,11,12,13,14,15}. Let event E={7,8,9,10,11,12,13,14,15}. Assume each outcome is equally likely. List the outcomes in E^{c}. Find P(E^{c}).

Solution:

Part 1:

E^{c} means compliment of the set E. A compliment of a set can be obtained by finding the difference of the set from the universal set. The universal set is the set which contains all the possible outcomes of the events which is S in this case.

So, compliment of E will be equal to S - E. S - E will result in all those elements of S which are not present in E. So, we can write:

E^{c}=S-E \\  \\ &#10;E^{c}=(4,5,6,7,8,9,10,11,12,13,14,15)-(7,8,9,10,11,12,13,14,15) \\  \\ &#10;E^{c}=(4,5,6)

Thus the set compliment of E will contain the elements {4,5,6}.So

E^{c} = {4,5,6}

Part 2)

P(E^{c}) means probability that if we select any number from the Sample Space S, it will belong the set E compliment.

P(E^{c}) = (Number of Elements in E^{c})/Number of elements in S

Number of elements in set S = n(S) = 12
Number of elements in set E^{c} = n(E^{c})=3

So, 

P(E^{c})= \frac{n(E^{c}) }{n(S)} \\  \\ &#10;P(E^{c})= \frac{3}{12} \\  \\ &#10;P(E^{c})= \frac{1}{4}
7 0
3 years ago
What expression is equivalent 19/38
Alex
I am not going to tell you the answer but i can tell you how to find it out. First you have to put 19/38 on a paper. Then multipy the numarator and denomanator by the same number on the top and bottom which is called a whole number. 19/38 times 2/2 or 3/3 or 4/4 or anything. Your answer is equivalent to 19/38
4 0
3 years ago
Read 2 more answers
Need Help...
Rudik [331]
<span>|7x-7|+3 = 4x+1  ⇒⇒⇒ add (-3) to both sides
</span>
<span>∴ |7x-7| = 4x - 2
</span>
According to the absolute rule
∴ 7x - 7 = 4x - 2    OR    -(7x - 7) = 4x - 2                                 
    7x - 4x = 7 - 2      l     7x - 7 = -4x + 2                              
   3x = 5                   l     7x + 4x = 2 + 7                                         
  x = 5/3                   l     11 x = 9  ⇒⇒⇒  x = 9/11

∴ x = 5/3  and  9/11


So, the correct answer is option <span>B. 5/3 and 9/11</span>


5 0
3 years ago
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