Answer:
Answer: b = 58/5 or 11 3/5 or 11.6 decimal
Step-by-step explanation:
Solve for b:
b - (3 + 2/5) = 8 + 1/5
Put 3 + 2/5 over the common denominator 5. 3 + 2/5 = (5×3)/5 + 2/5:
b - (5×3)/5 + 2/5 = 8 + 1/5
5×3 = 15:
b - (15/5 + 2/5) = 8 + 1/5
15/5 + 2/5 = (15 + 2)/5:
b - (15 + 2)/5 = 8 + 1/5
15 + 2 = 17:
b - 17/5 = 8 + 1/5
Put each term in b - 17/5 over the common denominator 5: b - 17/5 = (5 b)/5 - 17/5:
(5 b)/5 - 17/5 = 8 + 1/5
(5 b)/5 - 17/5 = (5 b - 17)/5:
(5 b - 17)/5 = 8 + 1/5
Put 8 + 1/5 over the common denominator 5. 8 + 1/5 = (5×8)/5 + 1/5:
(5 b - 17)/5 = (5×8)/5 + 1/5
5×8 = 40:
(5 b - 17)/5 = 40/5 + 1/5
40/5 + 1/5 = (40 + 1)/5:
(5 b - 17)/5 = (40 + 1)/5
40 + 1 = 41:
(5 b - 17)/5 = 41/5
Multiply both sides of (5 b - 17)/5 = 41/5 by 5:
(5 b - 17)/(5 1/5) = 1/5×1/(1/5) 41
1/5×1/(1/5) = 1:
5 b - 17 = 1/5×1/(1/5) 41
1/5×1/(1/5) = 1:
5 b - 17 = 41
Add 17 to both sides:
5 b + (17 - 17) = 17 + 41
17 - 17 = 0:
5 b = 41 + 17
41 + 17 = 58:
5 b = 58
Divide both sides of 5 b = 58 by 5:
(5 b)/5 = 58/5
5/5 = 1:
Answer: b = 58/5 or 11 3/5 or 11.6 decimal
X=((log(225000/200000)/log(1.03))
X=log(225,000÷200,000)÷log(1.03)
X=3.98 years
The answer is 16 days because 30/ 1.85 = 16 days
5y - 2x + 1 = 0.
5y = 2x-1.
y = 2/5 x - 2/5
this tells us that tan(theta) = 2/5
sin(theta)/sqrt(1-sin^2(theta)) = 2/5
x/sqrt(1-x^2)=2/5
x^2/(1-x^2)=4/25
25x^2=4-4x^2
29x^2=4
x^2=4/29
x = -2/sqrt(29) because quadrant III
cos(x) = sqrt(1-4/29) = -5/sqrt(29)
tan(theta)=2/5
cos(theta)=-5/sqrt(29)
sin(theta)=-2/sqrt(29)
cot(theta)=5/2
sec(theta)=-sqrt(29)/5
csc(theta)=-sqrt(29)/2
I believe A is the correct answer