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Sladkaya [172]
3 years ago
10

JJ: ANswer question for me(Tasha) WHat is 456789x456

Mathematics
2 answers:
Grace [21]3 years ago
7 0

Answer:

208295784

Step-by-step explanation:

456789 x 456 = 208295784

xxMikexx [17]3 years ago
5 0

Answer:

208295784

Step-by-step explanation:

You might be interested in
In the track meet I competed in the high jump and the pole vault. What is this called?
nata0808 [166]

Answer:

Within the parlance of Statistics, this is called Nominal Data.

Other examples of nominal data are:

  • Race
  • Country
  • Gender etc

Cheers

5 0
3 years ago
Can somebody please help me
erik [133]

Answer:

d=3 and e=-1

Step-by-step explanation:

d+e=2

d=2-e-----(1)

d-e=4-----(2)

substituting (1) in (2)

2-e-e=4

-2e=2

e=-1-----(3)

substituting (3) in (1)

d=2-(-1)

d=3

6 0
3 years ago
Help me plz 8th grade math need answers quick
mixer [17]

Answer:

25. Not a solution

26. Yes a solution

27. y= 2/3 x

28. y=3x+16

Step-by-step explanation:

25. The solution to a linear equation is the point (x,y). To find if an (x,y) is a solution, substitute it into the equation and see if it works.

y=4x-4 and (8,3)

3=4(8)-4

3=32-4

3=28

False

Not a solution.

26. Repeat 25 to solve 26 with y=5x-5 and (0,-5)

y=5x-5 and (0,-5)

-5=5(0)-5

-5=0-5

-5=-5

True

Yes a solution.

27. This line crosses through the origin is proportional and therefore has the form y=mx. It also has a gentle slant meaning that is less than 1/2 and goes in a positive direction. This means it is y=2/3 x.

28. Use inverse operations to rearrange the equation.

y-3x=16

y=16+3x

y=3x+16

8 0
3 years ago
A long jumper lifts off 3 m after starting his run, and lands 6 m later. When he is 8 m from the start line, he is 5 cm above an
slega [8]

Answer:

The equation of the parabola that models the path of the long jumper through the air is y = -x^{2}+12\cdot x -27.

Step-by-step explanation:

Mathematically, we know that parabolas are second-order polynomials and every second-order polynomials, also known as quadratic functions, can be constructed by knowing three different points of the curve. The standard form of the parabola is:

y = a\cdot x^{2}+b\cdot x + c

Where:

x - Horizontal distance from the start line, measured in meters.

y - Height of the long jumper, measured in meters.

a, b, c - Polynomial constants, measured in \frac{1}{m}, dimensionless and meters, respectively.

If we know that (x_{1},y_{1}) = (3\,m, 0\,m), (x_{2},y_{2}) = (8\,m, 0.05\,m) and (x_{3}, y_{3}) = (9\,m, 0\,m), this system of linear equations is presented below:

9\cdot a + 3\cdot b + c = 0 (Eq. 1)

81\cdot a + 9\cdot b + c = 0 (Eq. 2)

64\cdot a + 8\cdot b + c = 0.05 (Eq. 3)

The coefficients of the polynomial are, respectively:

a = -\frac{1}{100}, b = \frac{3}{25}, c = -\frac{27}{100}

The equation of the parabola that models the path of the long jumper through the air is y' = -\frac{1}{100}\cdot x^{2}+\frac{3}{25}\cdot x -\frac{27}{100}.

But we need y measured in centimeters, then, we use the following conversion:

y = 100\cdot y'

Then, we get that:

y = -x^{2}+12\cdot x -27

Where x and y are measured in meters and centimeters, respectively.

The equation of the parabola that models the path of the long jumper through the air is y = -x^{2}+12\cdot x -27.

4 0
3 years ago
Hcf of 14 154 and 28​
anyanavicka [17]

Answer:

14

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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