The standard equation for a circle with center at (h,k) and radius r is
(x-h)^2 + (y-k)^2 = r^2, where (h,k) is the center of the circle.
The formula for the circumference of a circle is C = 2pi*r. In this particular problem, we need to determine the radius of the circle. That radius is: r = C/[2pi]. Here, C = 22pi, so we get r = 22pi/[2pi], and so r^2 = 11^2.
Putting to use the given info, we have:
(x+14)^2 + (y-5)^2 = 11^2
Answer:
31
Step-by-step explanation:
Increases by 7 each time
✿ Domain is the Set of Values of x
⇒ Domain = { 10 , 15 , 19 , 32 }
✿ Range is the Set of Values of y (Images of x)
⇒ Range = { -1 , 5 , 9 }
First Option is the Answer
Answer:
84
Step-by-step explanation:
The interquartile range is obtained using the relation :
Third quartile (Q3). - First quartile (Q1)
From. The boxplot :
Q3 = 96
Q1 = 12
Interquartile range (IQR) = Q3 - Q1 = 96 - 12 = 84
C(F) is the degrees Celsius given the degrees Fahrenheit.<span />
