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3 years ago

Please help Given the replacement set {2, 3, 4, 5}, solve 6x – 4 =2 x + 16

Mathematics

1 answer:

rewona [7]3 years ago

3 0

Answer:

{5}

Step-by-step explanation:

6(5)-4 = 2(5)+16

30-4 = 10+16

26 = 26

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Please I need your help

BlackZzzverrR [31]

Answer:

the volume would change since the object is heavier

Step-by-step explanation:

I can't see other steps and the more the mass and the area of the object the more volume ots take up

8 0

3 years ago

Read 2 more answers

Which sequence is modeled by the graph below?

mariarad [96]

Answer:

$a_n=27\left(\dfrac{1}{3}\right)^{n-1}$

Step-by-step explanation:

From inspection of the graph, the given points are:

(2, 9)
(3, 3)
(4, 1)

If we draw a line through the given points, the line is a curve rather than a straight line. If the line was a straight line, the graph would be modeled as an arithmetic sequence. Therefore, as the line is a curve, the given points are modeling a geometric sequence.

General form of a geometric sequence:

$a_n=ar^{n-1}$

where:

a is the first term
r is the common ratio
$a_n$ is the nth term

Rewrite the given points as terms of the sequence:

(2, 9) ⇒ a₂ = 9
(3, 3) ⇒ a₃ = 3
(4, 1) ⇒ a₄ = 1

To find the common ratio r, divide consecutive terms:

$\implies r=\dfrac{a_3}{a_2}=\dfrac{3}{9}=\dfrac{1}{3}$

Calculate the first term (a) by substituting the found value of r and the given values of one of the terms into the formula:

$\implies a_2=9$

$\implies a\left(\dfrac{1}{3}\right)^{2-1}=9$

$\implies \dfrac{1}{3}a=9$

$\implies a=27$

Substitute the found values of r and a into the general formula to create the sequence modeled by the graph:

$a_n=27\left(\dfrac{1}{3}\right)^{n-1}$

Learn more about geometric sequences here:

brainly.com/question/25398220

brainly.com/question/27783194

5 0

1 year ago

Read 2 more answers

Ten college students were randomly selected. Their grade point averages (GPAs) when they entered the program were between 3.5 a

solong [7]

Answer:

The 95% confidence interval for the true slope is (0.03985, 0.14206).

Step-by-step explanation:

For the regression equation:

$\hat y=\alpha +\hat \beta x$

The (1 - α)% confidence interval for the regression coefficient or slope $(\hat \beta )$ is:

$Ci=\hat \beta \pm t_{\alpha/2, (n-2)}\times SE(\hat \beta )$

The regression equation for current GPA (Y) of students based on their GPA's when entering the program (X) is:

$\hat Y=3.584756+0.090953 X$

The summary of the regression analysis is:

Predictor Coefficient SE t-stat p-value

Constant 3.584756 0.078183 45.85075 5.66 x 10⁻¹¹

Entering GPA 0.090953 0.022162 4.103932 0.003419

The regression coefficient and standard error are:

$\hat \beta = 0.090953\\SE (\hat \beta)=0.022162$

The critical value of t for 95% confidence level and 8 degrees of freedom is:

$t_{\alpha/2, n-2}=t_{0.05/2, 10-2}=t_{0.025, 8}=2.306$

Compute the 95% confidence interval for $(\hat \beta )$ as follows:

$CI=\hat \beta \pm t_{\alpha/2, (n-2)}\times SE(\hat \beta )\\=0.090953\pm 2.306\times 0.022162\\=0.090953\pm 0.051105572\\=(0.039847428, 0.142058572)\\\approx (0.03985, 0.14206)$