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Svetllana [295]
3 years ago
11

Radon: The Problem No One Wants to Face" is the title of an article appearing in Consumer Reports. Radon is a gas emitted from t

he ground that can collect in houses and buildings. At certain levels it can cause lung cancer. Radon concentrations are measured in picocuries per liter (pCi/L). A radon level of 4 pCi/L is considered "acceptable." Radon levels in a house vary from week to week. In one house, a sample of 8 weeks had the following readings for radon level (in pCi/L).
1.9 2.3 5.7 5.2 1.9 8.8 3.9 7.3
(a) Find the mean, median, and mode. (Enter your answers to 2 decimal places.)
mean
median
mode
(b) Find the sample standard deviation, coefficient of variation, and range. (Enter your answers to 2 decimal places.)
s
CV %
range
Mathematics
1 answer:
brilliants [131]3 years ago
4 0

Answer:

a) \bar{x}=4.63 md=4.55 mo= 1.9 b) Sample Standard Deviation≈ 2.58 Coefficient of Variation=55.72% Sample Range=6.9

Step-by-step explanation:

a)

<u>Mean</u>

a)\bar{x}=\frac{1.9+ 2.3+ 5.7+ 5.2+ 1.9+ 8.8+ 3.9+ 7.3}{8} =\frac{37}{8}=4.625=\approx 4.63

For the <u>Median</u>, we have to order the entries. So, ordering it goes:

1.9 1.9 2.3 3.9 5.2 5.7 7.3 8.8

Since we have even entries \frac{\frac{n}{2}+\frac{n}{2} +1}{2}=\frac{4th+5th}{2}=\frac{3.9+5.2}{2}=4.55

mode

The mode for this data 1.9 1.9 2.3 3.9 5.2 5.7 7.3 8.8 is 1.9

b)

<u>Sample Standard Deviation</u>

Here it is the formula to calculate it:

_{x}=\sqrt{\frac{\sum (x_{i}-\bar{x})^{2}}{n-1}}\\ S_{x}=\sqrt{\frac{46.855}{7}}\approx 2.58

<u>Coefficient of Variation</u>

CV is the quocient between sample Standard deviation over Mean and it is used to make comparisons.

CV=\frac{S_x}{\bar{x}}*100%=\frac{2.58}{4.63} \approx 55.72%

<u>Range</u>

The difference between the highest and the lowest value of this sample

8.8-1.9=6.9

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