Question

Help pleasee solve i^100 - i^80 if i^2 = -1 and i^3 = -i

Answer 1

Answer:

Step-by-step explanation:

$i^{100} - i^{80}=i^{2*50} -i^{2*40}\\\\=(i^{2})^{50}-(i^{2})^{40}\\\\=(-1)^{50}-(-1)^{40}$

= 1 - 1

= 0