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3 years ago

Which pair of numbers has an LCM of 8

Mathematics

1 answer:

maxonik [38]3 years ago

3 0

Answer:

2,8

Step-by-step explanation:

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Find the value of each variables

kompoz [17]

Answer:

Step-by-step explanation:

Two similar triangles.

10/26 = y/13

y = 5

x² = 13² - y² = 144

x = 12

7 0

2 years ago

Giving 20 points ;(((((()

harkovskaia [24]

Answer:

$\large\boxed{3\div\dfrac{1}{3}}$

Step-by-step explanation:

1 has been divided into three equal parts. Each of these parts is 1/3. Let's calculate how many times 1/3 is in 3.

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2 years ago

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aksik [14]

Answer:

If asking for the distance, the answer would be C.

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2 years ago

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A pump fills a pool at the rate of 20 cubic meters in an hour. If each cubic meter of water costs $10, how many minutes will the

fomenos

The first thing any good mathematician does is convert the measurements to the same unit as what the question is asking. In this problem, it states that the pool fills at a rate of 20 cubic meters per hour. Just keep in mind that an hour is 60 minutes.

The next step is to see how many cubic meters will cost $300. This can be done by dividing 300 by 10. This gets you 30 cubic meters of water.

You already know that 60 minutes is 20 cubic meters of water. That leaves the remaining 10 cubic meters of water. By dividing the rate given, you get that 30 minutes is 10 cubic meters of water. Add the 60 and 30 together to get 90 minutes.

It will take 90 minutes for the pump to use $300.

7 0

3 years ago

A researcher compares the effectiveness of two different instructional methods for teaching electronics. A sample of 138 student

yan [13]

Answer:

The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the difference between population means is:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

The information provided is as follows:

$n_{1}= 138\\n_{2}=156\\\bar x_{1}=61\\\bar x_{2}=64.6\\\sigma_{1}=18.53\\\sigma_{2}=13.43$

The critical value of <em>z</em> for 98% confidence level is,

$z_{\alpha/2}=z_{0.02/2}=2.326$

Compute the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 as follows:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

$=(61-64.6)\pm 2.326\times\sqrt{\frac{(18.53)^{2}}{138}+\frac{(13.43)^{2}}{156}}\\\\=-3.6\pm 4.4404\\\\=(-8.0404, 0.8404)\\\\\approx (-8.04, 0.84)$

Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

5 0

2 years ago

Which pair of numbers has an LCM of 8​

Which pair of numbers has an LCM of 8