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Marizza181 [45]
3 years ago
6

Solve for m. 2 √5= 3 = 3 6+25 26-25 02.5-6

Mathematics
1 answer:
Sloan [31]3 years ago
5 0

Answer:

Simplify the matrix.

2√5=3=3,31,1,−3.5

Step-by-step explanation:

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Solve x2+12x=-11 by completing the square . Which is the the solution set of the equation?
Dmitriy789 [7]

Answer:

{- 11, - 1 }

Step-by-step explanation:

Since the coefficient of the x² term is 1 , to complete the square

add (half the coefficient of the x-term )² to both sides

x² + 2(6)x + 36 = - 11 + 36 ← complete the square on the left side

(x + 6)² = 25 ( take the square root of both sides

\sqrt{(x+6)^2} = ± \sqrt{25}

x + 6 = ± 5 ( subtract 6 from both sides )

x = - 6 ± 5

x = - 6 + 5 = - 1 or x = - 6 - 5 = - 11




8 0
3 years ago
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Help please! this is my third time posting this!! T.T
ArbitrLikvidat [17]

Answer:

see below

Step-by-step explanation:

24 - 3 x = -27

Subtract 24 from each side

24-24 - 3 x = -27-24

-3x =-51

Divide each side by -3

-3x/-3 = -51/-3

x = 17

Check

24 -3(17) = -27

24 -51 = -27

-27 = -27

8 0
3 years ago
Solve the equation. Check your solution. - 6y + 5 = 29y - 2​
mr_godi [17]

Answer:

y = 0.2

Step-by-step explanation:

Simplifying

-6y + 5 = 29y + -2

Reorder the terms:

5 + -6y = 29y + -2

Reorder the terms:

5 + -6y = -2 + 29y

Solving

5 + -6y = -2 + 29y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-29y' to each side of the equation.

5 + -6y + -29y = -2 + 29y + -29y

Combine like terms: -6y + -29y = -35y

5 + -35y = -2 + 29y + -29y

Combine like terms: 29y + -29y = 0

5 + -35y = -2 + 0

5 + -35y = -2

Add '-5' to each side of the equation.

5 + -5 + -35y = -2 + -5

Combine like terms: 5 + -5 = 0

0 + -35y = -2 + -5

-35y = -2 + -5

Combine like terms: -2 + -5 = -7

-35y = -7

Divide each side by '-35'.

y = 0.2

Simplifying

y = 0.2

3 0
3 years ago
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Find the area of the part of the plane z = ax + by + c that projects onto a region in the xy-plane with area
vlada-n [284]
Check the attached file for the solution.

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3 years ago
To show that polygon ABCDE is congruent to polygon FGHIJ, a must be used to make the two polygons coincide. A sequence of two tr
Sati [7]
Hello.

The minimum number of rigid transformations required to show that polygon ABCDE is congruent to polygon FGHIJ is 2 (translation and rotation). 

A rotation translation must be used to make the two polygons coincide. 

A sequence of transformations of polygon ABCDE such that ABCDE does not coincide with polygon FGHIJ is a translation 2 units down and a 90° counterclockwise rotation about point D 

Have a nice day
7 0
3 years ago
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