Answer:
Step-by-step explanation:
First, isolate sinx.
Subtract both sides by 1; after that, divide both sides by 2.
Now recall a unit circle. Sine is only negative in Q3 and Q4.
1/2 is 30° or π/6 for sine.
Finding the Q3 and Q4 angles.
<u>Q</u><u>3</u>
Using π + π/6 = 6π/6 + π/6 = 7π/6
<u>Q</u><u>4</u>
Using 2π - π/6 = 12π/6 - π/6 = 11π/6
Now we know that in Q3, sinx = -1/2 is 7π/6 and in Q4, it's 11π/6.
Thus:-
But since you did not specific the interval, assume that we are finding general solutions.
From Identity:
Therefore since x = 7π/6 and x = 11π/6:
where k is any integers.