Suppose an automobile manufacturer designed a radically new lightweight engine and wants to recommend the grade of gasoline that
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Answer:
Step-by-step explanation:
We have the two functions:
And we wish to find:
First, let’s find f(2) first. So, we will substitute 2 for x for f(x):
Hence, we can now substitute 3 for f(2):
Now, we can find g(6). Substitute 6 for t for g(t):
Therefore:
I assume there are some plus signs that aren't rendering for some reason, so that the plane should be 
.
You're minimizing
subject to the constraint 
. Note that 
and 
attain their extrema at the same values of 
, so we'll be working with the squared distance to avoid working out some slightly more complicated partial derivatives later.
The Lagrangian is
Take your partial derivatives and set them equal to 0:
Adding the first three equations together yields
and plugging this into the first three equations, you find a critical point at
.
The squared distance is then
, which means the shortest distance must be 
.
You're minimizing
The Lagrangian is
Take your partial derivatives and set them equal to 0:
Adding the first three equations together yields
and plugging this into the first three equations, you find a critical point at
The squared distance is then