6*2=12
32-12=20
20/2=10.
Perimeter is all the way around an object. So take 6 two times and minus that from 32. Answer of that divide by 2 to get the length. Length of one side is 10 ft.
Problem 7: Correct
Problem 8: Correct
Problem 9: Correct
The steps are below if you are curious
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Problem 7
S = 180*(n-2)
2340 = 180*(n-2)
2340/180 = n-2
13 = n-2
n-2 = 13
n = 13+2
n = 15
I'm using n in place of lowercase s, but the idea is the same. If anything, it is better to use n for the number of sides since S already stands for the sum of the interior angles. I'm not sure why your teacher decided to swap things like that.
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Problem 8
First find y
y+116 = 180
y+116-116 = 180-116
y = 64
which is then used to find x. The quadrilateral angles add up to 180*(n-2) = 180*(4-2) = 360 degrees
Add up the 4 angles, set the sum equal to 360, solve for x
x+y+125+72 = 360
x+64+125+72 = 360 ... substitution (plug in y = 64)
x+261 = 360
x+261-261 = 360-261
x = 99
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Problem 9
With any polygon, the sum of the exterior angles is always 360 degrees
The first two exterior angles add to 264. The missing exterior angle is x
x+264 = 360
x+264-264 = 360-264
x = 96
Translation:
R ( - 5, - 5 ) → R` ( - 4, 2 )
- 4 = - 5 + 1, 2 = - 5 + 7;
The translation rule:
( x , y ) → ( x + 1, y + 7 )
Coordinates of the point U are (- 5, 1 )
- 5 + 1 = - 4, 1 + 7 = 8
The image of U is :
U` ( - 4, 8 )
