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4 years ago

Solve the system of equations. Show ALL your work. Put your answer in the form of an ordered pair (x, y)

1 answer:

6 0

This should be easy because we just have to use substitution method. Substitute the value of x from the second equation into the x of the first equation.
-4(2y) + 11y = 15
-8y + 11y = 15
3y = 15 ; y = 5
Substitute this value of y to either the first or second equation.
x = 2(5) = 10
The ordered pair is therefore (10,5).

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Answer:

Answer is each large drink $1.25

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2 years ago

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Laura randomly pulled a marble from a bag and then replaced it.

marissa [1.9K]

Answer: C. 180 times

Step-by-step explanation:

From the 60 trials, the percentage of times Laura picked a green marble was:

= 100% - Percentage of times blue and red were picked

= 100% - 25% - 15%

= 60%

If these results were repeated with 300 trials, the number of times Laura would be expected to pick green would be:

= 60% * 300

= 180 times

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3 years ago

What is the product of 0.3 and 1,000

vichka [17]

The answer is equal to 300.

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3 years ago

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Estimate the minimum number of subintervals to approximate the value of Integral from negative 3 to 3 (2 x squared plus 9 )dx wi

vichka [17]

Answer:

The value of n for (a) n=425. (b) n=0.

Step-by-step explanation:

Given integration is,

$\int_{-3}^{3}f(x)=\int_{-3}^{3}(2x^2+9)dx$

(a) For Trapezoidal Rule : Composite error is,

$E_T=-\frac{(b-a)^3}{12n^2}f''(x_m)$

Where, f''(x_m)=greatest value of |f''(x)|= |4|=4, a=-3, b=3. Therefore to find the minimum number of subinterval,

$|E_T|\leq | \frac{(b-a)^3}{12n^2}f''(x)|$ |

$\leq \frac{4(-3-3)^3}{12n^2}$

$=\frac{72}{n^2}$

According to the question, we must choose n such that,

$\frac{72}{n^2}$

$\implies n>424.2640686$

So we can take n=425.

(b) For Simpson 1/3 rule : Composite error is,

$E_S=-\frac{(b-a)^5}{180n^4}f^{(iv)}(x_m)$

where, $f^{(x_m)}=\textit{greatest value of} |f^{(iv)}(x)|$

In this problem $f^{(iv)}(x)=0$ , so that,

$|E_S|\leq 0$

that is there exist no error. So n=0.

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3 years ago

What is the probability that a standard number cube will show a two, five, or six when it is rolled?

tia_tia [17]

Answer:

$p=0.5$

Step-by-step explanation:

A standard die has six numbers (1 through 6). That means there is a 1/6 probability of rolling any one number. There is a 3/6 probability of rolling one of the selected numbers which simplifies to 1/2 or 0.50

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3 years ago