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adell [148]
3 years ago
13

Sam is 2 years and his mother is 28 years old. In how many years will Sam's mother be 3 times as old as he will be?

Mathematics
2 answers:
xz_007 [3.2K]3 years ago
5 0

Answer:

x=13

Step-by-step explanation:

Let:

A_s=Age\hspace{3}of\hspace{3}Sam\\A_m=Age\hspace{3}of\hspace{3}Sam's\hspace{3}mother\\x=Years\hspace{3}required\hspace{3}for\hspace{3}Sam's\hspace{3}mother\hspace{3}be\hspace{3}3\hspace{3}times\hspace{3}as\hspace{3}old\hspace{3}as\hspace{3}sam\hspace{3}will\hspace{3}be

Now, let's write the problem in form of an algebraic equation. Basically, the future age will be the current age plus x quantity of years. So mathematically we can calculate in how many years will Sam's mother be 3 times as old as he will be as:

A_m+x=3(A_s+x)

Solving for x:

A_m+x=3A_s+3x\\3x-x=A_m-3A_s\\2x=A_m-3A_s\\x=\frac{A_m-3A_s}{2}

Replacing the values of A_m and A_s

x=\frac{28-3(2)}{2}=\frac{28-6}{2}=\frac{22}{2}=11

Hence, the years required for Sam's mother be 3 times as old as sam will be is 11

stepan [7]3 years ago
4 0
When Sam is 13 his mother will be 39 which is 3 times as old as he is. So Sam's mother will be 3 times as old as Sam will be in 11 years. (Your answer is 11 years.)
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<span>"The company pays $55 a day for food and lodging and $0.45 for each mile traveled" means that if she travels m miles and is on a trip for x days then Rita will receive:

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Part A: 55x+135=2,335.

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Read 2 more answers
If sin ⁡x=725, and 0 ∠ x ∠ pi/2, what is the tan (x - pi/4)
krok68 [10]

Tan(x-\frac{\pi }{4}) = \frac{-17}{31}

<u>Step-by-step explanation:</u>

Here we have ,  sin ⁡x=7/25( given sin x = 725 which is not possible ) , 0 . Let's find tan (x - pi/4):

⇒ Tanx = \frac{sinx}{cosx}

⇒ Tanx = \frac{sinx}{\sqrt{1-(sinx)^{2}}}

⇒ Tanx = \frac{\frac{7}{25}}{\sqrt{1-(\frac{7}{25})^{2}}}

⇒ Tanx = {\frac{7}{25}}{\sqrt{(\frac{625}{625-49})^{}}}

⇒ Tanx = {\frac{7}{25}}(\frac{25}{24} )

⇒ Tanx = {\frac{7}{24}}

Now , Tan(x-\frac{\pi }{4}) = \frac{Tanx - Tan(\frac{\pi }{4} )}{1+ Tanx(Tan(\frac{\pi }{4} )}

⇒ Tan(x-\frac{\pi }{4}) = \frac{Tanx -1}{1+ Tanx(1)}

⇒ Tan(x-\frac{\pi }{4}) = \frac{\frac{7}{24}  -1}{1+\frac{7}{24} }

⇒ Tan(x-\frac{\pi }{4}) = \frac{\frac{7-24}{24} }{\frac{7+24}{24} }

⇒ Tan(x-\frac{\pi }{4}) = \frac{-17}{24} (\frac{24}{31} )

⇒ Tan(x-\frac{\pi }{4}) = \frac{-17}{31}

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