Prove that if m + n and n + p are even integers, where m, n, and p are integers, then m + p is even.
m=2k-n, p=2l-n
Let m+n and n+p be even integers, thus m+n=2k and n+p=2l by definition of even
m+p= 2k-n + 2l-n substitution
= 2k+2l-2n
=2 (k+l-n)
=2x, where x=k+l-n ∈Z (integers)
Hence, m+p is even by direct proof.
Answer:
Step-by-step explanation:
This operation would result in the "midpoint" of the line segment.
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We need to refer to the population distribution of all college statistics textbook prices.
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From the given information;
We are being given the sample size and the mean that has already been computed. Thus, to determine the probability of a more extreme mean, we need the t-test statistics value. In this case, we will need the sample mean, thus we need to refer to the population distribution of all college statistics textbook prices.
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Step-by-step explanation: she only has 3 because of herself
I hate dividing fractions but I think -2/16 off of my best hunch.
