F(x) = 6x + 7; x = -3

Mathematics

2 answers:

jok3333 [9.3K]3 years ago

8 0

Answer:

1+80×70-80+55-6+12065

ryzh [129]3 years ago

7 0

Answer: -11

Step-by-step explanation:

Plug in -3 into X

6(-3)+ 7

Solve : -18+7 = -11

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astra-53 [7]

56 is the right answer

4 0

3 years ago

2x ≤ 12 Select the appropriate response A2x ≤ 12 B)x≤4 C)x≤6 D)x ≤ 10

Monica [59]

Answer:

c x ≤ 6

Step-by-step explanation:

2x ≤ 12

Divide each side by 2

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8 0

3 years ago

Prove that the diagonals of a parallelogram bisect each other

Nady [450]

Answer:

[ See the attached picture ]

The diagonals of a parallelogram bisect each other.

✧ Given : ABCD is a parallelogram. Diagonals AC and BD intersect at O.

✺ To prove : AC and BD bisect each other at O , i.e AO = OC and BO = OD.

Proof : $\begin{array}{ |c| c | c | } \hline \tt{SN}& \tt{STATEMENTS} & \tt{REASONS}\\ \hline 1& \sf{In \: \triangle ^{s} \:AOB \: and \: COD } \\ \sf{(i)}& \sf{ \angle \: OAB = \angle \: OCD\: (A)}& \sf{AB \parallel \: DC \: and \: alternate \: angles} \\ \sf{(ii)} &\sf{AB = DC(S)}& \sf{Opposite \: sides \: of \: a \: parallelogram} \\ \sf{(iii)} &\sf{ \angle \: OBA= \angle \: ODC(A)} &\sf{AB \parallel \:DC \: and \: alternate \: angles} \\ \sf{(iv)}& \sf{ \triangle \:AOB\cong \triangle \: COD}& \sf{A.S.A \: axiom}\\ \hline 2.& \sf{AO = OC \: and \: BO = OD}& \sf{Corresponding \: sides \: of \: congruent \: triangle}\\ \hline 3.& \sf{AC \: and \: BD \: bisect \: each \: other \: at \: O}& \sf{From \: statement \: (2)}\\ \\ \hline\end{array}. Proved ✔$

♕ And we're done! Hurrayyy! ;)

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