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Tju [1.3M]
3 years ago
11

If the discount rate is 20%, how much would the discount be on a pair of boots that cost $75?

Mathematics
1 answer:
sergejj [24]3 years ago
3 0
20% of off $75 is $60.
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Guys Help!! I Don´t Know How To Do This!!
Shkiper50 [21]

Answer:

Frank

Step-by-step explanation:

First let's start by calculating the speed of each runner.

Let's use feet per second

Frank's speed is already given in feet per second: 14 feet/second

We are given that Jake runs 382 feet in 38 seconds. To bring this down to feet/second we need to divide both numbers by 38.

382/38=10.05 feet/second (about)

We are given that Will runs 1 mile in 394 seconds. 1 mile is equivalent to 5280 feet. Now we divide both numbers by 394 to bring it down to feet/second.

5280/394=13.401  feet/second (about)

We are given that Ron runs 555 feet in 1 minute. 1 minute is equivalent to 60 seconds. Now we divide both numbers by 60 to bring it down to feet/second.

555/60=9.25 feet/second

After comparing all the speeds, we can conclude that Frank runs the fastest

5 0
2 years ago
17/20
Lena [83]

Answer:

2.39 cm

Step-by-step explanation:

6 0
3 years ago
Which reason justifies step 2 in the proof
faust18 [17]

Answer:

Step-by-step explanation:

Given: ∠N≅∠S, line l bisects TR at Q.

To prove: ΔNQT≅ΔSQR

Proof:

From  ΔNQT and ΔSQR

It is given that:

∠N≅∠S (Given)

∠NQT≅∠SQR(Vertical opposite angles)

and TQ≅QR ( Definition of segment bisector)

Thus, by AAS rule,

ΔNQT≅ΔSQR

Hence proved.

Statement                                                 Reason

1. ∠N≅∠S                                                    given

2. ∠NQT≅∠SQR                            Vertical angles are congruent

3.  line l bisects TR at Q.                            given

4. TQ≅QR                                      Definition of segment bisector

5. ΔNQT≅ΔSQR                           AAS theorem

Hence proved.

Thus, option D is correct.

3 0
3 years ago
HELPPPP MEEEEEEEE ! Can you have a right triangle where the lengths of the legs are whole numbers and the length of the hypotenu
MArishka [77]
No, u cant

a^2 + b^2 = c^2.....pythagorean theorem used on only right triangles...where a and b are the legs and c is the hypotenuse

a^2 + b^2 = 23^2
a^2 + b^2 = 529...so u would have to find 2 square numbers that add up to 529. There aren't any.
3 0
3 years ago
Read 2 more answers
HELP!! A,b,or C need it asap
AVprozaik [17]

Answer:

the answer is b

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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