Round $8.0443 to the nearest cent

Which equation represents the line that has a slope of 1/2 and contains the point (0, 3)?

RideAnS [48]

Y - 3 = 1/2 (x) ......

4 0

3 years ago

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8. At a wholesale food distribution center, the price of sugar has increased 6.3% annually since 1980.

Nitella [24]

Answer: A. $4.12

Step-by-step explanation:

Y=a(1+r/n)^nt is the equation we use to solve this.

a= $0.43

t=37 - take 1980 and subtract it from 2017

r= .063 - the 6.3% goes into a decimal

n = 1

Y= ?

Y= 0.43( 1+ .063/1) ^1*37

Y= 0.43 (1.063) ^37

Y= 4.12

7 0

3 years ago

A computer can be classified as either cutting dash edge or ancient. Suppose that 94% of computers are classified as ancient.

taurus [48]

Answer:

(a) 0.8836

(b) 0.6096

(c) 0.3904

Step-by-step explanation:

We are given that a computer can be classified as either cutting dash edge or ancient. Suppose that 94% of computers are classified as ancient.

(a) Two computers are chosen at random.

The above situation can be represented through Binomial distribution;

$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 2 computers

r = number of success = both 2

p = probability of success which in our question is % of computers

that are classified as ancient, i.e; 0.94

LET X = Number of computers that are classified as ancient

So, it means X ~ $Binom(n=2, p=0.94)$

Now, Probability that both computers are ancient is given by = P(X = 2)

P(X = 2) = $\binom{2}{2}\times 0.94^{2} \times (1-0.94)^{2-2}$

= $1 \times 0.94^{2} \times 1$

= 0.8836

(b) Eight computers are chosen at random.

The above situation can be represented through Binomial distribution;

$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 8 computers

r = number of success = all 8

p = probability of success which in our question is % of computers

that are classified as ancient, i.e; 0.94

LET X = Number of computers that are classified as ancient

So, it means X ~ $Binom(n=8, p=0.94)$

Now, Probability that all eight computers are ancient is given by = P(X = 8)

P(X = 8) = $\binom{8}{8}\times 0.94^{8} \times (1-0.94)^{8-8}$

= $1 \times 0.94^{8} \times 1$

= 0.6096

(c) Here, also 8 computers are chosen at random.

The above situation can be represented through Binomial distribution;

$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 8 computers

r = number of success = at least one

p = probability of success which is now the % of computers

that are classified as cutting dash edge, i.e; p = (1 - 0.94) = 0.06

LET X = Number of computers classified as cutting dash edge

So, it means X ~ $Binom(n=8, p=0.06)$

Now, Probability that at least one of eight randomly selected computers is cutting dash edge is given by = P(X $\geq$ 1)

P(X $\geq$ 1) = 1 - P(X = 0)

= $1 - \binom{8}{0}\times 0.06^{0} \times (1-0.06)^{8-0}$

= $1 - [1 \times 1 \times 0.94^{8}]$

= 1 - $0.94^{8}$ = 0.3904

Here, the probability that at least one of eight randomly selected computers is cutting dash edge is 0.3904 or 39.04%.

For any event to be unusual it's probability is very less such that of less than 5%. Since here the probability is 39.04% which is way higher than 5%.

So, it is not unusual that at least one of eight randomly selected computers is cutting dash edge.

7 0

3 years ago

Given x = 5, y = -6, z = -2, evaluate z - yx

Andreyy89

Answer: 28

Step-by-step explanation: Plugging them in, it would be -2 - (-6)(5).

- 2 - (-30)

-2 + 30

28

8 0

3 years ago

Help me!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

ahrayia [7]

Answer:

9. x=-6, y=0

10. x=-9, y=-10

11. x=3, y=-1

Step-by-step explanation:

$2x-9y=-12\\3x+18y=-18$

Multiply the first equation by 2.

$4x-18y=-24\\3x+18y=-18$

Add the equations.

$7x=-42$

$x=-6$

We figured out x now we have to figure out y. To figure out y plug in x into any equation.

$2(-6)-9y=-12$

$-12-9y=-12$

$-9y=0$

$y=0$

Your answer is x = -6 and y = 0 for number nine.

$6x+3y=24\\2x+3y=-12$

Change the signs of the second equation becuase 3y and 3y are both positive. We need one of them to be negative.

$6x+3y=24\\-2x-3y=12$

Add them.

$4x = 36$

$x=9$

Now we have to figure out y.

$2(9)+3y=-12$

$18+3y=-12$

$3y=-30$

$y=-10$

x=-9 and y=-10 is your answer to number ten.

$10x+5y=25\\-7x-3y=-18$

$30x+15y=75\\-35x-15y=-90$

$-5x=-15$

$x=3$

$-7(3)-3y=-18$

$-21-3y=-18$

$-3y=3$

$y=-1$

x=3 and y=-1 is the answer to number eleven. I hope this helps! Let me know if I got anything wrong.

4 0

3 years ago

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