Answer:
The answer to your question is x = 3; y = 3
Step-by-step explanation:
Data
angle = 45°
Opposite side = x
Adjacent side = y
hypotenuse = 3√2
To solve this problem, use trigonometric functions.
1) To find x, use the trigonometric function sine.
sin Ф = Opposite side / hypotenuse
-Solve for Opposite side (x)
Opposite side = hypotenuse x sin Ф
-Substitution
Opposite side = 3√2 sin 45
-Simplification
Opposite side = 3√2 (1 / √2)
Opposite side = 3(1)
-Result
x = 3
2) To find y use the trigonometric function cosine
cos Ф = Adjacent side / hypotenuse
-Solve for Adjacent side
Adjacent side = hypotenuse x cos Ф
-Substitution
Adjacent side = 3√2 x cos 45
-Simplification
Adjacent side = 3√2 x (1/√2)
Adjacent side = 3(1)
-Result
y = 3
Answer:
25
Step-by-step explanation:
13+1.50m
13+1.50(8)
13+12
25
Answer:
In order to solve this problem, you have to find the lowest common denominator. Take multiples of both 6 and 4 and see which is the lowest you have in common.
4: 4, 8, 12, 16, 20
6: 6, 12, 18, 24
So 12 is the lowest common multiple....
5/6 x ?/? = ?/12 (you have to multiply the numerator and the denominator by the same number)
3/4 x ?/? = ?/12 (you have to multiply the numerator and the denominator by the same number)
When the denominators are the same, you can subtract the numerators. The denominator will stay 12!
Step-by-step explanation:
YAY! I want a brain
Answer:
The given relation R is equivalence relation.
Step-by-step explanation:
Given that:
Where 
is the relation on the set of ordered pairs of positive integers.
To prove, a relation R to be equivalence relation we need to prove that the relation is reflexive, symmetric and transitive.
1. First of all, let us check reflexive property:
Reflexive property means:
Here we need to prove:
As per the given relation:
which is true.
R is reflexive.
2. Now, let us check symmetric property:
Symmetric property means:
Here we need to prove:
As per the given relation:
means 
means 
Hence true.
R is symmetric.
3. R to be transitive, we need to prove:
means 
.... (1)
means 
...... (2)
To prove:
To be 
we need to prove: 
Multiply (1) with (2):
So, R is transitive as well.
Hence proved that R is an equivalence relation.
