The prime factorization of 343 is 7^3. So the cube root of 343 (7^3) is just 7.
Irrational: Cannot be expressed in the form of a/b. 7/1 = 7 No
Rational: Can be expressed in the form of a/b. 7/1 = 7 Yes
Integer: Set of all negative and positive numbers (not a fraction). 7 is a positive number. Yes
Whole: Set of numbers ranging from 0 to infinity (not a fraction). 7 is a positive whole number. Yes
Natural: Set of all positive numbers from 1 to infinity (not a fraction). 7 is positive. Yes
Answer:
2, 7, 27, 42
Step-by-step explanation:
y = 5*1 -3 =2
y = 5*2 -3 =7
y = 5*6 -3 = 27
y = 5*9 -3 = 42
Answer:
43,872
Step-by-step explanation:
The growth of cell phone subscribers in Centerville can be modeled by an exponential function.
y = ab^x . . . . . where a = initial value, b = growth factor
The growth rate is given as 75% per year, so x will have units of years. It will be zero for the year 1985. The growth factor is ...
b = 1 + growth rate = 1 +0.75 = 1.75
Then the model is ...
y = 285·1.75^x
__
For x = 1994 -1985 = 9, the number of subscribers is modeled as ...
y = 285·1.75^9 ≈ 43,872
The model predicts 43,872 cell phone subscribers in 1994.
Answer:
$425.6 should be budgeted for weekly repairs and maintenance.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean 
and standard deviation 
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean $400 and standard deviation $20.
This means that 
How much should be budgeted for weekly repairs and maintenance to provide that the probability the budgeted amount will be exceeded in a given week is only 0.1?
This is the 100 - 10 = 90th percentile, which is X when Z has a p-value of 0.9, so X when Z = 1.28.
$425.6 should be budgeted for weekly repairs and maintenance.
