All categories

2 years ago

D. 20.0 Math question no Guessing and Please show work

Mathematics

1 answer:

Vikki [24]2 years ago

6 0

Pythagoras theorem
${a}^{2} = {b}^{2} + {c}^{2}$
Now in your case
${b}^{2} = {9}^{2} + {12}^{2}$
$\sqrt{b}$

You might be interested in

Please divide using long division.<br> (x3 - 7x2 + 14)/(X - 5)

MAVERICK [17]

X^3 - 2x - 10 - 36/x-5

4 0

2 years ago

Is the circumference of all circles about 3 times greater than their diameters. and why?

stira [4]

Answer:

<h2>Yes the circumference is about times greater than their diameters</h2>

Step-by-step explanation:

We will approach this problem by doing a check

Say the diameter of a circle is 4 cm

Hence the radius is 3 cm

We know that the circumference is $C=2\pi r$

$C=2*3.142*2= 12.57cm$

The circumference is about 3 time bigger than the diameter

Let us try another case say the diameter is 6 cm

The radius is 3 cm

$C=2*3.142*3= 18.85cm$

8 0

2 years ago

1/9(-9x+18)-1/5(10+15x)

garri49 [273]

Answer:

-4x

Step-by-step explanation:

5 0

2 years ago

Evaluate the line integral for x^2yds where c is the top hal fo the circle x62 _y^2 = 9

natulia [17]

Parameterize $C$ by

$\mathbf r(t)=\langle x(t),y(t)\rangle=\langle3\cos t,3\sin t\rangle$

where $0\le t\le\pi$ . Then the line integral is

$\displaystyle\int_Cx^2y\,\mathrm dS=\int_{t=0}^{t=\pi}x(t)^2y(t)\left\|\frac{\mathrm d\mathbf r(t)}{\mathrm dt}\right\|\,\mathrm dt$
$=\displaystyle\int_{t=0}^{t=\pi}(3\cos t)^2(3\sin t)\sqrt{(-3\sin t)^2+(3\cos t)^2}\,\mathrm dt$
$=\displaystyle3^4\int_{t=0}^{t=\pi}\cos^2t\sin t\,\mathrm dt$

Take $u=\cos t$ , then

$=\displaystyle-3^4\int_{u=1}^{u=-1}u^2\,\mathrm du$
$=\displaystyle3^4\int_{u=-1}^{u=1}u^2\,\mathrm du$
$=\displaystyle2\times3^4\int_{u=0}^{u=1}u^2\,\mathrm du$
$=54$

6 0

2 years ago

Add 7 plus 8, then add a to the result. Write an expression for the sequence of operations described.

Ipatiy [6.2K]

Answer:

(7 + 8) + a is your answer

4 0

2 years ago