So your equation would be 8a+10=11d-6
First: you would combine like terms so normally you would take away the smaller number. So to cancel out the negative 6 you added you add positive six to the negative 6 so you would get 0 and whatever you do to one side you have to do to the other so you would do 10 + 6. Your new equation would be 8a+16=11d. Now you do -16 to both sides. So your new equation would be 8a= 11d - 16. Now you divide by 8. So your final equation would be a=11d-2.
Answer:
A
Step-by-step explanation:
3x^2 - 8x + 4 = 0
x= [-b +or- square root (b^2 - 4ac)] ÷ 2a
= [-(-8) +or- square root (-8)^2 - 4(3)(4)] ÷ 2(3)
= [8 +or- square root 16] ÷ 6
= 2 or 2/3
Step-by-step explanation:
I don't know this math yet
sorry
1 litre of 10% solution contains 100mL of iodine
1 litre of 90% solution contains 900mL of iodine
Mixing them will produce 2 litres of solution containing 1000mL of iodine which is 50% iodine.
To produce 8 litres of 50% iodine they can mix 4 litres of 10% and 4 litres of 90%
Answer:
Answer: The mean increases by 3
Step-by-step explanation:
The original data set is
{50, 76, 78, 79, 79, 80, 81, 82, 82, 83}
The outlier is 50 because it is not near the group of values from 76 to 83 which is where the main cluster is.
The original mean is M = (50+76+78+79+79+80+81+82+82+83)/10 = 77
If we take out the outlier 50, the new mean is N = (76+78+79+79+80+81+82+82+83)/9 = 80
So in summary so far
old mean = M = 77
new mean = N = 80
The difference in values is N-M = 80-77 = 3
So that's why the mean increases by 3
