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3 years ago

I really need help...Will mark brainiest

Mathematics

1 answer:

chubhunter [2.5K]3 years ago

3 0

Answer:

x² + 18x +81

x² - 14x +49

4x²- 4x - 1

Step-by-step explanation:

multiply the x in the first parentheses by x and 9 in the other parentheses and

multiply the 9 in the first parentheses by x and 9 in the other parentheses and add all together

(x+9)(x+9)

x² + 9x + 9x + 81

x² + 18x +81

multiply the x in the first parentheses by x and -7 in the other parentheses and multiply the -7 in the first parentheses by x and -7 in the other parentheses and add all together

(x-7)(x-7)

x² -7x - 7x +49

x² - 14x +49

(2x-1)² is the same as (2x-1)(2x-1)

multiply the 2x in the first parentheses by 2x and -1 in the other parentheses and multiply the -1 in the first parentheses by 2x and -1 in the other parentheses and add all together

(2x-1)(2x-1)

4x²-2x-2x+1

4x²- 4x - 1

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Can someone help me?

loris [4]

Answer:

i do not know srry

Step-by-step explanation:

i think u should try and solve it with a better teacher

4 0

3 years ago

Read 2 more answers

Need help fast please thanks

murzikaleks [220]

Answer:

c = 41 ft

Step-by-step explanation:

To solve this problem, we can use the pythagorean theorem, which is defined by the formula $a^2+b^2=c^2$ . We are given both the lengths of the legs, so all we need to do is to plug them both in and solve for c:

$9^2+40^2 = c^2\\c^2 = 81 + 1600\\c^2 = 1681\\c = 41$

This is the first option.

8 0

3 years ago

Two cars are traveling down the highway with the same speed. If the first car increases its speed by 1km/hr, and the other car d

Olegator [25]

Answer:

The speed of the cars is $32 \frac{km}{h}$

Step-by-step explanation:

First we must first have the clear concept that $speed=\frac{distance}{time}$ or $s=\frac{d}{t}$

Our question is the speed of the cars then the variable to clear will be s.

Let's raise the equation for each car taking into account that we have the following data:

Car 1: $s_{1}=s+1$ , $t_{1}=2$ and $d_{1}= d_{2}$

Car 1: $s_{2}=s-10$ , $t_{2}=3$ and $d_{1}= d_{2}$

The two cars travel the same distance so we will raise the distance formula for each car and then match them.

Car 1

$d_{1}=s_{1}*t_{1}$

$d_{1}=(s+1)*2$

$d_{1}=2s+2$

Car 2

$d_{2}=s_{2}*t_{2}$

$d_{2}=(s-10)*3$

$d_{2}=3s.30$

$d_{1}=d_{2}$

$2s+2=3s-30$

$2+30=3s-2s$

$32=s$

The speed of the cars is 32 km/hr

7 0

3 years ago

Solve the expression 8 x 5 − 12 x one third + 5 using PEMDAS

skelet666 [1.2K]

Answer:41

Step-by-step explanation: Multiplication and division goes first so 8x5=40 12x1/3=4 so 40-4+5 and you do addition and subtraction left to right 40-4=36+5=41

8 0

3 years ago

Please answer and explain

sashaice [31]

8=2*2*2=2^3
32=2*2*2*2*2=2^5
[8^(2/3)] / [32^(2/5)] = [(2^3)^(2/3)] / [(2^5)^(2/5)] =
= [2^(3*2/3)] / [2^(5*2/5)]= [2^2] / [2^2] = 4/4 = 1
Answer: 1

4 0

2 years ago