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Black_prince [1.1K]
3 years ago
5

I really need help...Will mark brainiest

Mathematics
1 answer:
chubhunter [2.5K]3 years ago
3 0

Answer:

x² + 18x +81

x² - 14x +49

4x²- 4x - 1

Step-by-step explanation:

multiply the x in the first parentheses by x and 9 in the other parentheses and

multiply the 9 in the first parentheses by x and 9 in the other parentheses and add all together

(x+9)(x+9)

x² + 9x + 9x + 81

x² + 18x +81

multiply the x in the first parentheses by x and -7 in the other parentheses and multiply the -7 in the first parentheses by x and -7 in the other parentheses and add all together

(x-7)(x-7)

x² -7x - 7x +49

x² - 14x +49

(2x-1)² is the same as (2x-1)(2x-1)

multiply the 2x in the first parentheses by 2x and -1 in the other parentheses and multiply the -1 in the first parentheses by 2x and -1 in the other parentheses and add all together

(2x-1)(2x-1)

4x²-2x-2x+1

4x²- 4x - 1

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<h3>How to solve the trigonometric equations?</h3>

<u>Equation 1: 1 - cos(x) = 2 - 2sin²(x) from (-π, π)</u>

The equation can be split as follows:

y = 1 - cos(x)

y = 2 - 2sin²(x)

Next, we plot the graph of the above equations (see graph 1)

Under the domain interval (-π, π), the curves of the equations intersect at:

(-π/3, 0.5) and (π/3, 0.5)

Hence, the solutions to 1 - cos(x) = 2 - 2sin²(x) from (-π, π) are (-π/3, 0.5) and (π/3, 0.5)

<u>Equation 2: 4cos⁴(x) - 5cos²(x) + 1 = 0 from [0, 2π)</u>

The equation can be split as follows:

y = 4cos⁴(x) - 5cos²(x) + 1

y = o

Next, we plot the graph of the above equations (see graph 2)

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Hence, the solutions to 4cos⁴(x) - 5cos²(x) + 1 = 0 from [0, 2π) are (π/3, 0), (2π/3, 0), (π, 0), (4π/3, 0) and (5π/3, 0)

Read more about trigonometry equations at:

brainly.com/question/8120556

#SPJ1

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