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skelet666 [1.2K]
3 years ago
15

Solve for m < LMN.......

Mathematics
1 answer:
lukranit [14]3 years ago
7 0

Answer:

m< LMN = 111°

Step-by-step explanation:

m< LMO + m<OMN = m< LMN

58 + 53 = 111

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3/5 rational number on a number line
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3/5 is a rational number. It is a fraction that is made from two integers - 3 and 5.

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The points: ( -2, 7) and ( 6, 2) are 2 points on a line. Find the slope of the line. *
Step2247 [10]

Answer: A

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3 years ago
Solve the absolute value equation |2x|+5=17
kondaur [170]

Answer:

x=6/x=-6

Step-by-step explanation:

subtract 5 from each side to isolate the absolute value function

2x=12

divide to isolate the x simplified down all the way// x=6, absolute value will have a positive and a negative answer.

7 0
3 years ago
Please help with this question.
barxatty [35]

Answer:

Step-by-step explanation:

The first thing we have to do is find the measure of angle A using the fact that the csc A = 2.5.

Csc is the inverse of sin. So we could rewrite as

\frac{1}{sinA}=2.5 or more easy to work with is this:

\frac{1}{sinA} =\frac{2.5}{1}

and cross multiply to get

2.5 sinA = 1 and

sinA=\frac{1}{2.5} which simplifies to

sin A = .4

Using the 2nd and sin keys on your calculator, you'll get that the measure of angle A is 23.58 degrees.

We can find angle B now using the Triangle Angle-Sum Theorem that says that all the angles of a triangle have to add up to equal 180.  Therefore,

angle B = 180 - 23.58 - 90 so

angle B = 66.42

The area of a triangle is

A =\frac{1}{2}bh where h is the height of the triangle, namely side AC; and b is the base of the triangle, namely side BC. To find first the height, use the fact that angle B, the angle across from the height, is 66.42, and the hypotenuse is 3.9.  Right triangle trig applies:

sin(66.42)=\frac{h}{3.9} and

3.9 sin(66.42) = h so

h = 3.57

Now for the base.  Use the fact that angle A, the angle across from the base, measures 23.58 degrees and the hypotenuse is 3.9. Right triangle trig again:

sin(23.58)=\frac{b}{3.9} and

3.9 sin(23.58) = b so

b = 1.56

Now we can find the area:

A=\frac{1}{2}(1.56)(3.57) so

A = 2.8 cm squared

3 0
3 years ago
Consider the type of clothes dryer (gas or electric) purchased by each of five different customers at a certain store. a. If the
krok68 [10]

There lies a typo-error when typing the part (b) of this question, which have identified and sort out; here is the right question below.

Consider the type of clothes dryer (gas or electric) purchased by each of five different customers at a certain store. a. If the probability that at most one of these purchases an electric dryer is .428, what is the probability that at least two purchase an electric dryer? b. If P(all five purchase gas) .116 and P(all five purchase electric) .005, what is the probability that at least one of each type is purchased?

Answer:

a) 0.572

b) 0.879

Step-by-step explanation:

Given that:

there are two types of dryer.

Gas dryer

Electric dryer

So,  from the question a. If the probability that at most one of these purchases an electric dryer is .428, what is the probability that at least two purchase an electric dryer

Let us represent M with the event that at most one purchase is an electric dryer

Let use M' (i.e complement of M) to represent the event that at least two purchase an electric dryer.

Then if P (M) = 0.428

P(M') = 1 - P(M)

P(M') = 1 - 0.428

P(M') = 0.572

∴ the probability that at least two purchase an electric dryer = 0.572

b)

If P(all five purchase gas) .116 and P(all five purchase electric) .005, what is the probability that at least one of each type is purchased?

Let N represent the event that all five purchases are gas dryer

Then P (N) = 0.116

Let Q represent the event that all five purchase are electric dryer

Then P(Q) = 0.005

So (N∪Q); which is read as (N union Q) is the event that only one type of dryer is purchased.

so P(N∪Q) = ( 0.116+ 0.005)

= 0.121

Then the complement of (N∪Q) ; i.e (N∪Q)' signifies the event that at least one of each type is purchased;

So, P(N∪Q)' = 1 - (N∪Q)

P(N∪Q)' = 1 - 0.121

P(N∪Q)' = 0.879

∴ the probability that at least one of each type is purchased = 0.879

6 0
3 years ago
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