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Greeley [361]
3 years ago
9

The points: ( -2, 7) and ( 6, 2) are 2 points on a line. Find the slope of the line. *

Mathematics
1 answer:
Step2247 [10]3 years ago
7 0

Answer: A

Hope this helped!

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Find the second derivative of 2x^3-3y^2=8​
Umnica [9.8K]

Answer:

\frac{d^2y}{dx^2}=\frac{x(2y-x^3)}{y^3}

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<u>Find the first implicit derivative using implicit differentiation</u>

<u />2x^3-3y^2=8\\\\6x^2-6y\frac{dy}{dx}=0\\ \\-6y\frac{dy}{dx}=-6x^2\\ \\\frac{dy}{dx}=\frac{x^2}{y}

<u>Use the substitution of dy/dx to find the second derivative (d²y/dx²)</u>

<u />\frac{d^2y}{dx^2}=\frac{(y)(2x)-(x^2)(\frac{dy}{dx})}{y^2}\\ \\\frac{d^2y}{dx^2}=\frac{2xy-(x^2)(\frac{x^2}{y})}{y^2}\\\\\frac{d^2y}{dx^2}=\frac{2xy-\frac{x^4}{y}}{y^2}\\\\\frac{d^2y}{dx^2}=\frac{x(2y-x^3)}{y^3}

5 0
3 years ago
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