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3 years ago

Help me with this please (sorry for the bad picture)

Mathematics

2 answers:

oee [108]3 years ago

7 0

Answer:

2^3 x 3 should be connected to 24, 2 x 3^3 should be connected to 57, and 2 x 3^2 x 5 should be connected to 90.

Also, when I say something like 2^3, I mean 2 to the power of 3. That also applies to 3^3 (3 to the power of 3) and 3^2 (3 to the power of 2).

Elenna [48]3 years ago

4 0

THANK YOU.

You might be interested in

Rama09 [41]

Answer:

m∠AOB=139°

Step-by-step explanation:

m∠AOB+m∠BOC=180°

m∠AOB=8x+51°

m∠BOC=6x-25°

$\tt 8x+51+6x-25=180$

$\tt 14x+26=180$

$\tt 14x=180-26$

$\tt \cfrac{14x}{14} =\cfrac{154}{14}$

$\tt x=11$

m∠AOB:-

$\tt 8(11)+51$

$\tt =88+51$

$\tt =139^{o}$

Therefore, m∠AOB=139°

7 0

2 years ago

Compare. Write <,>,or =.<br> 250 lb __ 0.25 T

Llana [10]

Answer: 0.25 T is bigger

Step-by-step explanation:

0.25 T = 500 lb

4 0

3 years ago

What answer to 10 + a - 5 + 2a

Tanzania [10]

Answer:

5+3a

Step-by-step explanation:

10 + a -5 + 2a

5+a+2a

5+3a

5 0

3 years ago

If the area of a sector is 100 ft^2 and the radius of the circle is 22 ft what is the central angle measure for that sector and

ahrayia [7]

Answer:

$\displaystyle \theta=0.413\ rad$

Step-by-step explanation:

<u>Area of a Circular Sector</u>

Given a circle of radius r, the area of a circular sector defined by a central angle θ (in radians) is given by

$\displaystyle A=\frac{1}{2}r^2\theta$

And the length of the arc is:

$L=\theta r$

We know the area of the sector is 100 square feet and the radius is r=33 ft, thus:

$\displaystyle 100=\frac{1}{2}r^2\theta$

Solving for θ:

$\displaystyle \theta=\frac{200}{r^2}$

$\displaystyle \theta=\frac{200}{22^2}$

$\displaystyle \theta=0.413\ rad$

The arc length is:

$L=0.413* 22$

L= 9.086 feet

6 0

3 years ago

Lesson 17 Practice Problems

Elina [12.6K]

Answer:

(a) we get that the fewest number of packages of cups and napkins should buy is 24.

(b) Number of sets of 3 packages of Cups and 2 packages of Napkins will be there.

Step-by-step explanation:

Given that,

Cups are sold in packages of 8.

Napkins are sold in package of 12.

To find:- (a) What is the fewest number of packages of cups and the fewest number of packages of napkins that can be purchased so there will be the same number of cups as napkins?

From the Question,

We have to least number of packages of cups and napkins So, we find the

L.C.M of the given data because it provide the least common multiple.

So, L.c.m of 8 & 12 is

$8= 2\times 2\times2$

$12= 2\times2\times3$

$L.c.m = 2\times2\times2\times3 = 24$

Here we get that the fewest number of packages of cups and napkins should buy is 24.

(b) How many sets of cups and napkins will there be?

Again,

Number of packages of cups should buy = $\frac{24}{8} = 3$

Number of packages of Napkins should buy = $\frac{24}{12} = 2$

Hence

Number of sets of 3 packages of Cups and 2 packages of Napkins will be there.

4 0

3 years ago

Help me with this please (sorry for the bad picture) ​

Help me with this please (sorry for the bad picture)