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3241004551 [841]
3 years ago
5

12. Ms. Smith keeps eight different cookbooks on a shelf in one of her kitchen cabinets. How many ways can the eight cookbooks b

e arranged on the shelf?
Mathematics
1 answer:
Ghella [55]3 years ago
6 0

Answer:

The number of ways are 40320.

Step-by-step explanation:

Consider the provided information.

Ms. Smith keeps eight different cookbooks on a shelf in one of her kitchen cabinets.

We need to determine the number of different ways to put eight cookbooks on the shelf.

We need to select 8 cookbooks taking 8 at a time.

So use the permutation formula: ^{n}P_{n}

Substitute n=8 and simplify.

^8P_8=\frac{8!}{(8-8)!}\\8!=40320

Hence, the number of ways are 40320.

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Someone help me please ​
nirvana33 [79]

Answer:

426.9km^{2}

Step-by-step explanation:

Area of the shaded region→

A=\frac{1}{2}*40*27-\pi *6^{2}

→ 540-113.04

→426.9

---------

hope it helps..

have a great day!!!

8 0
2 years ago
I need help. Thank you.
Oduvanchick [21]

Answer:

D

A=-5

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Express the integral as a limit of Riemann sums. Do not evaluate the limit. (Use the right endpoints of each subinterval as your
Veronika [31]

The expression of integral as a limit of Riemann sums of given integral \int\limits^5_b {1} \, x/(2+x^{3}) dxis 4 \lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3} from i=1 to i=n.

Given an integral \int\limits^5_b {1} \, x/(2+x^{3}) dx.

We are required to express the integral as a limit of Riemann sums.

An integral basically assigns numbers to functions in a way that describes displacement, area, volume, and other concepts that arise by combining infinite data.

A Riemann sum is basically a certain kind of approximation of an integral by a finite sum.

Using Riemann sums, we have :

\int\limits^b_a {f(x)} \, dx=\lim_{n \to \infty}∑f(a+iΔx)Δx ,here Δx=(b-a)/n

\int\limits^5_1 {x/(2+x^{3}) } \, dx=f(x)=x/2+x^{3}

⇒Δx=(5-1)/n=4/n

f(a+iΔx)=f(1+4i/n)

f(1+4i/n)=[n^{2}(n+4i)]/2n^{3}+(n+4i)^{3}

\lim_{n \to \infty}∑f(a+iΔx)Δx=

\lim_{n \to \infty}∑n^{2}(n+4i)/2n^{3}+(n+4i)^{3}4/n

=4\lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3}

Hence the expression of integral as a limit of Riemann sums of given integral \int\limits^5_b {1} \, x/(2+x^{3}) dxis 4 \lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3} from i=1 to i=n.

Learn more about integral at brainly.com/question/27419605

#SPJ4

5 0
1 year ago
Which of the following numbers is irrational? <br><br><br> Please help!!
Nastasia [14]
Irratonal numbers can't be written as a/b where a and b are integers and b≠0

so if it can be written in form a/b then it is not irrational

\sqrt{36}=6=\frac{6}{1}, it's rational

1/5 is rational

\sqrt{60}=2\sqrt{15} it's irrational because we can't simplify the square root further

6.3=6.3/1=63/100, rationanl



answer is \sqrt{60} is irrational
7 0
3 years ago
If f (x) = 4x - 11 , What is the value of f(5)<br> a. 20x - 55<br> b. 34<br> c. 9<br> d. 4
kramer

Answer:C

Step-by-step explanation:

C

5 0
3 years ago
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